32 2/5 ÷ 2 7/10
let's turn above into improper fractions:
32 2/5 ----> 162/5
2 7/10 -----> 27/10
so,
162/5 ÷ 27/10 -------> 162/5 * 10/27 = 12 necklaces
Answer:
30
Step-by-step explanation:
Because of the following statement is not true no.of atoms
We know that
if the club includes one set of identical
triplets wearing matching clothes
then
the number of different arrangements that are
possible is
10! / 3! = (10*9*8*7*6*5*4*3!)/3!
=604,800
The answer is
<span>604,800</span>
Answer:
that = 8 and if you want to see more you can go on
Hey, let's figure this out together. :)
The answer is 1 and 6. Now we can prove that is true.
1 x 6 = 6
1 + (6) = 7
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