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natta225 [31]
3 years ago
11

A girl and a puppy are 540 feet apart when they start running towards each other. The girl runs at a speed of 15 feet per second

, and the puppy runs at a speed of 12 feet per second. How soon will they meet?
Mathematics
2 answers:
Lerok [7]3 years ago
6 0

Answer: 20 seconds

Step-by-step explanation:

The distance is 540 feet

speed of the girl = 15ft/s

speed of the puppy = 12 ft/s

If we stand in the frame of reference where the girl is still, in this frame the speed of the puppy will be equal to the speed of the puppy in our previus frame plus the speed of the girl in the previous frame (because they are running in opposite directions)

S = 15 ft/s + 12ft/s = 27ft/s

Now we can use the equation:

time = distance/speed

T = 540ft/27ft/s = 20s

alexdok [17]3 years ago
4 0

Answer:

20 secs

Step-by-step explanation:

The distance is 540 feet

speed of the girl = 15ft/s

speed of the puppy = 12 ft/s

If we stand in the frame of reference where the girl is still, in this frame the speed of the puppy will be equal to the speed of the puppy in our previus frame plus the speed of the girl in the previous frame (because they are running in opposite directions)

S = 15 ft/s + 12ft/s = 27ft/s

Now we can use the equation:

time = distance/speed

T = 540ft/27ft/s = 20s

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Trava [24]

Answer:

88.88% probability that it endures for less than a year and a half

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 66, \sigma = 10

The next career begins on Monday; what is the likelihood that it endures for less than a year and a half?

One year has 52.14 weeks. So a year and a half has 1.5*52.14 = 78.21 weeks.

So this probability is the pvalue of Z when X = 78.21.

Z = \frac{X - \mu}{\sigma}

Z = \frac{78.21 - 66}{10}

Z = 1.22

Z = 1.22 has a pvalue of 0.8888

88.88% probability that it endures for less than a year and a half

6 0
3 years ago
What is the range of the function f(x) = −(x + 3)2 + 7? all real numbers less than or equal to 7 all real numbers greater than o
ss7ja [257]
<span>all real numbers less than or equal to 7</span>
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Read 2 more answers
Help me... :/<br><br> Find the measure of each exterior angle of a regular 45-gon.
GuDViN [60]

Answer:

7740° / 45

Step-by-step explanation:

The sum of the interior angles is given by this formula: (n - 2) * 180°. So a regular 45-gon would have interior angles that add up to: (45 - 2) * 180°. = 43 * 180°. = 7740°. Now divide that by the 45 angles to find the measure of one interior angle

hope that helped :(

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3 years ago
What is the value of x in the equation<br> 4z +16<br> 12<br> = х - 4?
Serhud [2]
<h3>Solution:</h3>

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<h3>Answer:</h3>

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7 0
2 years ago
The admission fee is $1.50 for children and $4.00 for adults. If 2700 people enter and $7800 is collected how many children and
mash [69]

Number of children attended is 1200 and number of adults attended is 1500

<h3><u>Solution:</u></h3>

Given that,

Admission fee for each children = $ 1.50

Admission fee for each adult = $ 4.00

Let "c" be the number of children attended

Let "a" be the number of adults attended

Given that 2700 people enter and $7800 is collected

Number of children attended + number of adults attended = 2700

c + a = 2700  -------- eqn 1

Also given that $7800 is collected

Number of children attended x Admission fee for each children + number of adults attended x Admission fee for each adult = 7800

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Let us solve eqn 1 and eqn 2 to find values of "a" and "c"

From eqn1,

a = 2700 - c ----- eqn 3

Substitute eqn 3 in eqn 2

1.5c + 4(2700 - c) = 7800

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-2.5c = -3000

c = 1200

Therefore from eqn 3,

a = 2700 - 1200

a = 1500

Therefore number of children attended = c = 1200

number of adults attended = a = 1500

3 0
3 years ago
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