Answer:
I think it's c but I'm not 100 percent sure
Answer:
dy/dx = 0
Step-by-step explanation:
In y + y^2 = 10
Differentiating In y = 1/ydy/dx
Differentiating y^2 = 2ydy/dx
Differentiating a constant (10) = 0
1/ydy/dx + 2ydy/dx = 0
dy/dx(1/y + 2y) = 0
dy/dx = 0/(1/y + 2y) = 0
If x were positive, y would have to be a larger negative number.
Suppose x = 10. y would have to be negative 11+.
In other words, the absolute value of y would have to be greater than the value of x
Answer:
27/20
Step-by-step explanation:
1.35=27/20
Given:
f (-6) = 10 and f (2) = 10?
To find:
The linear function f.
Solution:
If f(x)=y, then the function passes through (x,y).
We have, f (-6) = 10 and f (2) = 10, it means the function passes through (-6,10) and (2,10). So, the equation is




Adding 10 on both sides, we get

Function form is

Therefore, the required function is
. It is a constant function.