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dedylja [7]
3 years ago
6

Use Green's Theorem to evaluate F · dr. C (Check the orientation of the curve before applying the theorem.) F(x, y) = e−x + y2,

e−y + x2 , C consists of the arc of the curve y = cos(x) from − π 2 , 0 to π 2 , 0 and the line segment from π 2 , 0 to − π 2 , 0
Mathematics
1 answer:
Yuki888 [10]3 years ago
3 0

Notice that C is traversed clockwise. Green's theorem applies to curves with a counterclockwise orientation, so we'll have to multiply the area integral by -1.

By Green's theorem, with the vector field \vec F(x,y)=P(x,y)\,\vec\imath+Q(x,y)\,\vec\jmath,

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=-\iint_D\left(\frac{\partial Q}{\partial x}-\frac{\partial P}{\partial y}\right)\,\mathrm dA

where D is the region with boundary C. The partial derivatives are

\dfrac{\partial(e^{-y}+x^2)}{\partial x}=2x

\dfrac{\partial(e^{-x}+y^2)}{\partial y}=2y

so that the double integral is

\displaystyle\iint_D\left(\frac{\partial Q}{\partial x}-\frac{\partial P}{\partial y}\right)\,\mathrm dA=\int_{-\pi/2}^{\pi/2}\int_0^{\cos x}2(y-x)\,\mathrm dy\,\mathrm dx=\boxed{\frac\pi2}

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Rickey has 7 over 8 cup of cereal in a bowl. He then gave two 1 over 4 cups of cereal from his bowl to his little sister. Which
NeX [460]

Answer:

5/8 cup left

Step-by-step explanation:

7/8 - 1/4

1/4=2/8

7/8-2/8

5/8

5 0
3 years ago
The profits of mr cash’s company is represented by the equation p(t)=-3t^2+18t-4, where p(t) is the amount of profit in hundreds
eduard
We have that

<span>p(t)=-3t^2+18t-4

using a graphing tool, we can see the maximum of the graph
(see the attached figure)

A) </span><span>In what year of operation does Mr. Cash’s business show maximum profit?

</span>Mr. Cash’s business show maximum profit at year 3 (maximum in the parabole)

<span>B) What is the maximum profit? 

23 (hundred of thousand of dollars) = 2.300.000 dollars

</span>c) What time will it be two late?
 
(This is the time when the graph crosses zero and the profits turn into losses )

5.77 years, or an estimate of about  69 months.

4 0
3 years ago
Maggie earns money from working at the pet store and answering phones. She earns $10 each hour she works at the pet store and $0
kvv77 [185]

115 = 10X + 0.25(60)

115 = 10x +15 (this is the equation to use)

100=10x

x=10 hours

4 0
3 years ago
Below are survival times (in days) of 13 guinea pigs that were injected with a bacterial infection in a medical study:
tresset_1 [31]

Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

The dataset is given as:

  • 91 83 84 79 91 93 95 97 97 120 101 105 98

Sort the dataset in ascending order

  • 79 83 84 91 91 93 95 97 97 98 101 105 120

<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

Q1 = \frac{N +1}{4}th

So, we have:

Q1 = \frac{13 +1}{4}th

Q1 = \frac{14}{4}th

Q1 = 3.5th

This is the average of the 3rd and the 4th element

Q1 = \frac{1}{2} \times (84 + 91)

Q1 = 87.5

<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

Q3 =  3 \times \frac{N +1}{4}th

So, we have:

Q3 =  3 \times \frac{13 +1}{4}th

Q3 =  3 \times 3.5th

Q3 =  10.5th

This is the average of the 10th and the 11th element.

Q_3 =\frac12 \times (98 + 101)

Q_3 =99.5

<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

IQR = Q_3 -Q_1

IQR = 99.5 - 87.5

IQR = 12

Also, we have:

IQR(1.5) = 12 \times 1.5

IQR(1.5) = 18

<h3>The outlier range</h3>

The lower and the upper outlier range are calculated as follows:

Lower = Q_1 - IQR(1.5)

Lower = 87.5- 18

Lower = 69.5

Upper = Q_3 + IQR(1.5)

Upper = 99.5 + 18

Upper = 117.5

120 is greater than 117.5.

Hence, the dataset has an outlier and the outlier is 120

Read more about outliers at:

brainly.com/question/9933184

6 0
2 years ago
Help!!!! please!!!!<br> thank you!!!!!!
pentagon [3]

Answer:

18) 6x^2-7x-5

19) 20x^2+17x-63

20) 18x^2-20x+2

21) 5x^2+42x+16

Step-by-step explanation:

Perimeter=length×breadth

18) (3x-5)(2x+1)

=6x^2+3x-10x-5

=6x^2-7x-5

19) (4x+9)(5x-7)

=20x^2-28x+45x-63

=20x^2+17x-63

20) (18x-2)(x-1)

=18x^2-18x-2x+2

=18x^2-20x+2

21) (5x+2)(x+8)

=5x^2+40x+2x+16

=5x^2+42x+16

6 0
3 years ago
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