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Gwar [14]
3 years ago
8

The question is down below please help

Mathematics
2 answers:
Inessa [10]3 years ago
6 0

Answer:

last one

Step-by-step explanation:

Vlad1618 [11]3 years ago
6 0

Answer:

4 (6-k)

the bottom one

Step-by-step explanation:

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How can the average rate of change be identified for a function?
Digiron [165]

Answer:

Rateofchange=\frac{f(x_2)-f(x_1)}{x_2-x_1}

where x₁ and x₂ are values in the interval [x,y] respectively

Step-by-step explanation:

Well, first to determine the average rate of change of a function, you should have the interval of the values of x for the function.

So lets assume you have a function;

f(x)=x^3-4x

And the interval as [1,3]

Then the average rate of change for the function f(x) will be;

=\frac{f(x_2)-f(x_1)}{x_2-x_1}

where x₁ and x₂ are the interval coordinates x,y respectively. In this case x₁=1 and x₂=3

To find the average rate of change in this example will be;

=\frac{f(x_2)-f(x_1)}{x_2-x_1} \\\\=f(x_2)=f(3)=3^3-4(3)=27-12=15\\\\=f(x_1)=f(1)=1^3-4(1)=1-4=-3\\\\\\=x_2-x_1=3-1=2\\\\\\=\frac{15--3}{2} \\\\=\frac{18}{2} =9

8 0
3 years ago
1. M is the midpoint of LN and O is the midpoint of NP.
Reptile [31]
1. M is the midpoint of LN and O is the midpoint of NP. This makes the triangle MNO equal to half of LNP. Then you can get this equation
MO= (1/2) LP

If you insert MO = 2x +6 and LP = 8x – 20 the calculation would be:
2x+6= (1/2)( 8x-20)
2x+6= 4x-10
2x-4x= -10 - 6
-2x= -16
x=8

2. Centroid is the point that intersects with three median lines of the triangle. The centroid should divide the median lines into 1:2 ratio. In AC lines, A located in the base so A.F:FC would be 1:2

Then, the answer would be:
A.F= 1/(1+2) * AC
A.F= 1/3 * 12= 4

FC= 2/(1+2) * AC
FC= 2/3 * 12= 8

3. Since
∠BAD=∠DAC
∠ABD=∠ACD
AD=AD
The triangle ABD and ACD are similar. You can get this equation
BD=DC
x+8= 3x+12
x-3x= 12-8
-2x=4
x=-2

DC=3x+12= 3(-2) +12= 6

4. Orthocenter made by intersection of triangle altitude
A
BC lines slope would be (-4)-(-1)/1-4= -3/-3= 1. The altitude line slope would be -1, the function would be:
y=-x +a
0= 1+a
a=-1
y=-x-1
B
AC lines slope would be (-4)-(-1)/1-0= -3. The altitude line slope would be 1/3, the function would be:
y=1/3x+a
-1=1/3(4)+a
a=-7/3
y=1/3x - 7/3

C
BC lines slope would be (-1)-(-1)/4 = 0/4. 
The line would be 
0=x+a
a=-1
0=x-1
x=1

y=-x-1 = 1/3x-7/3
-x-(1/3x)=-7/3 +1
-4/3x= -4/3
x=1

y=-x-1
y=-1-1= -2
The orthocenter would be (1,-2)

5. 
a. Circumcenter: the intersection of perpendicular bisector lines<span>
b. Incenter: the intersection of bisector lines
c. Centroid: </span>the intersection of median lines<span>
d. Orthocenter: </span>the intersection of altitude lines
5 0
3 years ago
Which equation has a slope m=- 4/3
wariber [46]
Y=mx+b
m=slope

so it is y=-4/3x+b

d is answer
4 0
3 years ago
Read 2 more answers
Solve this problem on paper using all four steps. A girl scout troop sold cookies. If the girls sold 5 more boxes the second wee
zhenek [66]
Assume the girls sold X boxes in the first week. They sold in the second week X+5 and 2X+10 in the third week.

The sum X + X + 5 + 2X + 10 = 431
4X = 416. Therefore X = 104
The answers are:
a0 = 104
a1 = 109
a2 = 218

Hope that helps you :)
6 0
3 years ago
Write an exponential function y = abx for a graph that includes (2, 24) and (3, 48).
labwork [276]
I think you mean y=ab^x.
First, plug in the values of x=2 and y=24 for the first equation, and x=3 and y=48 for the second one:

24 = ab^2
48 = ab^3

divide equation 2 by equation 1:
2 = b^1

or, more simply:
2 = b

now plug b into one of the equations to get "a":

24 = a*2^2
24 = a*4
6 = a

So, the answer is y = 6(2)^x
(I think you need to specify the power of x in your answers)
7 0
3 years ago
Read 2 more answers
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