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KengaRu [80]
3 years ago
12

4 Solve the system of equations using the substitution method. y = 2 2x+y=8

Mathematics
1 answer:
Sindrei [870]3 years ago
5 0

Answer:  2

Step-by-step explanation:

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6/12 + 1/3 Simplify completely, show all work.
marissa [1.9K]
If you multiply the numerator and the denominator of 1/3 by 4, you will get a common denominator. 

1/3 = 4/12

Then you can add:

6/12 +4/12 = 10/12

Just add the top 2 numbers and the bottom 2 stay the same. Then you can simplify. 2 goes into both 10 and 12, so divide them both by 2 and you get 5/6 as your answer.
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4 years ago
What is the slope of the line that passes through the points listed in the table?
lana66690 [7]
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3 years ago
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Triangle XYZ, X equals 27 cm, Y equals 79 cm and angle C equals 142Degrees. Find the length of Z, to the nearest centimeter.
Oksi-84 [34.3K]

Given:

In triangle XYZ, x = 27 cm, y = 79 cm and \angle C=142^\circ.

To find:

The length of z.

Solution:

In triangle XYZ, using the Law of cosine, we get

z^2=x^2+y^2-2xy\cos Z

Putting the given values in the above formula, we get

z^2=(27)^2+(79)^2-2(27)(79)\cos (142^\circ)

z^2=729+6241-4266(-0.788)

z^2=6970+3361.608

z^2=10331.608

Taking square root on both sides.

z=\pm \sqrt{10331.608}

z=\pm 101.6445178

Approx the above value to the nearest number and side length cannot be negative. So,

z\approx \pm 102\text{ cm}

Therefore, the length of z is about 102 cm.

4 0
3 years ago
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G(x)=10x+8. What is the value of g(5)?
kenny6666 [7]
5(x)=10x+8 so x is equal to -3
7 0
2 years ago
Make x the subject of these equations.
shepuryov [24]

(1)a(x + b) = c \\ ax + ab = c \\ ax = c - ab \\  \frac{ax}{a } =  \frac{c - ab}{a}   \\ x =  \frac{c - ab}{a}

(2)8(x + a) = b \\ 8x + 8a = b \\ 8x = b - 8a \\  \frac{8x}{8}  =  \frac{b - 8a}{8}  \\ x =  \frac{b - 8a}{8}

(3)a(x - 7) = b \\ ax - 7a = b \\ ax = b + 7a \\  \frac{ax}{a}  =  \frac{b + 7a}{a}  \\ x =  \frac{b + 7a}{a}

(4)c(2  + x) = 6 \\ 2c + cx = 6 \\ cx = 6 - 2c \\  \frac{cx}{c}  =  \frac{6 - 2c}{c}  \\ x =  \frac{6 - 2c}{c}

8 0
4 years ago
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