Find the product of (X-3)^2

............°_°.............

Rasek [7]

Answer:

3/4 and 0.95 would both result in a reduction.

Step-by-step explanation:

multiplying by anything less than 1 will make it smaller which both 3/4 and 0.95 are smaller than 1.

8 0

3 years ago

Read 2 more answers

. A fence encloses a triangular field. There is

poizon [28]

Answer:

16 posts

Step-by-step explanation:

<u>Sides are:</u>

20 ft, 25 ft and 35 ft

<u>There are following number of posts on each of the sides:</u>

20 ft side ⇒ 20/5 = 4
25 ft side ⇒ 25/5 = 5
35 ft side ⇒ 35/5 = 7

<u>Total number:</u>

4 + 5 + 7 = 16 posts

6 0

3 years ago

Which function is increasing at the highest rate? A. B. A linear function on a coordinate plane passes through (minus 1, 3), and

xenn [34]

The highest rate on increasing is of 12x -6y = -24; Option B is the correct answer.

The options are given in the image attached with the answer

<h3>What is a Function ?</h3>

A function is a law that relates a dependent variable and an independent variable.

It is asked among the options given , which is increasing at the highest rate.

To increase at a rate , the value of the slope , m should be > 0

For the Option 1

for a straight line function , the slope is given by

m = ( y₂ -y₁)/(x₂-x₁)

m = ( -3 -3)/(2- (-1)) = -6 /3 = -2

Therefore the function is decreasing

For Option 2

12x - 6y = -24

-6y = -12x -24

y = 2x +4

m = 2 (increasing)

For option 3

m = (-4 + 5)/(2-1) = 1

For Option 4

(8,0) (0,-4)

m = (-4 -0) /(0-8) = 4/8 = 1/2

The highest rate on increasing is of 12x -6y = -24

Therefore Option B is the correct answer.

To know more about Function

brainly.com/question/21145944

#SPJ1

6 0

2 years ago

The profit that a vendor makes per day by selling x elephant ears is given by the function P(x)= -0.004x^2+3.2x-200. Find the nu

dezoksy [38]

Answer:

The number of elephant ears that must be sold to maximize profit is 400.

Step-by-step explanation:

Given that,

The profit that a vendor makes per day is given by

P(x)= - 0.004x² +3.2 x -200

where x is number of elephant ears.

P(x)= - 0.004x² +3.2 x -200

Differentiating with respect to x

P'(x)= - 0.008x+3.2

Again differentiating with respect to x

P''(x) = -0.008

For maximum or minimum P'(x)=0

- 0.008x+3.2=0

⇒0.008x=3.2

$\Rightarrow x=\frac{3.2}{0.008}$

⇒ x = 400

$P''(x)|_{x=400} = -0.008$

Since at x=400, P''(x)<0, the profit is maximize.

P(400) = -0.004×400²+3.2×400-200

=440

The number of elephant ears that must be sold to maximize profit is 400.

3 0

3 years ago

State the domain restriction(s) in interval notation of \displaystyle f\left(g\left(x\right)\right)f(g(x)) given: \displaystyle

DENIUS [597]

Answer:

The interval notation for the domain is $[\frac{23}{3},\infty ]$ .

Step-by-step explanation:

Consider the provided information.

It is given that $\:f\left(x\right)=\sqrt{3x-2},\:\text{ and }\:g\left(x\right)=x-7$

We need to find the value of $f\left(g\left(x\right)\right)$ .

Put the value of g(x) in $f\left(g\left(x\right)\right)$ .

$f\left(g\left(x\right)\right)=f(x-7)$ ....(1)

Now, put x=x-7 in $\:f\left(x\right)=\sqrt{3x-2}$

$\:f\left(x-7\right)= \sqrt{3(x-7)-2}$

$\:f\left(x-7\right)= \sqrt{3x-21-2}$

$\:f\left(x-7\right)= \sqrt{3x-23}$

From equation 1.

$f\left(g\left(x\right)\right)=\:f\left(x-7\right)= \sqrt{3x-23}$

The domain of the function is the set of input values for which a function is defined.

Here, the value of $3x-23$ should be greater or equal to 0 as the square root of a negative number is not real.

Domain= $3x-23\geq0$

$x\geq\frac{23}{3}$

The value of x is all real number greater than $\frac{23}{3}$ .

Hence, the interval notation for the domain is $[\frac{23}{3},\infty ]$ .

7 0

3 years ago