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aleksklad [387]
3 years ago
13

Wheel I has diameter 23.4. Wheel ll has diameter 18.0. Round the diameter of each wheel to the nearest inch. About how much fart

her will Wheel l travel in one rotation?
Mathematics
2 answers:
11111nata11111 [884]3 years ago
8 0

Answer:

Wheel1 = 147inches , wheel 2 = 113inches

Wheel 1 will travel 147 revolutions.

Step-by-step explanation:

Finding the circumference of both wheels

Wheel 1 = 2 pi r = 2 × 3.142 × 23.4 = 147.05 inches. To the nearest inches = 147inches

Wheel 2 = 2 pi × r = 2 × 3.142 × 18 = 113.11inches . To the nearest inches = 113inches.

I rotation = 1 revolution

In 1 rotation, wheel 1 will travel= 147 × 1 = 147 revolutions.

Arisa [49]3 years ago
4 0

Answer:

16 inch

Step-by-step explanation:

Wheel I has diameter 23.4.

Wheel ll has diameter 18.0

  • Diameter of Wheel 1 to the nearest inch = 23 inch
  • Diameter of Wheel 2 to the nearest inch = 18 inch

The distance which each wheel will travel is determined by the circumference of the wheel.

Circumference of a Circle =\pi d

Distance Traveled by Wheel 1 in One Rotation =23\pi

Distance Traveled by Wheel 2 in One Rotation =18\pi

Therefore, the distance which Wheel 1 travels further =23\pi-18\pi=5\pi =15.7 inch

The distance farther is 16 inch to the nearest inch.

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6 1/3 divided by 2 1/2 = x

Step-by-step explanation:

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3 years ago
How many triangles can be made if one angle of a triangle is 95 degrees and another angle is obtuse?
const2013 [10]

That would be zero.


Obtuse means more than 90 degrees. A triangle's angles add up to 180 degrees so can't have two obtuse angles.



7 0
3 years ago
99 POINT QUESTION, PLUS BRAINLIEST!!!
Elden [556K]
We draw region ABC. Lines that connect y = 0 and y = x³ are vertical so:
(i) prependicular to the axis x - disc method;
(ii) parallel to the axis y - shell method;
(iii) parallel to the line x = 18 - shell method.

Limits of integration for x are easy x₁ = 0 and x₂ = 9.
Now, we have all information, so we could calculate volume.

(i)

V=\pi\cdot\int\limits_a^bf^2(x)\, dx\qquad\implies \qquad a=0\qquad b=9\qquad f(x)=x^3


V=\pi\cdot\int\limits_0^9(x^3)^2\, dx=\pi\cdot\int\limits_0^9x^6\, dx=\pi\cdot\left[\dfrac{x^7}{7}\right]_0^9=\pi\cdot\left(\dfrac{9^7}{7}-\dfrac{0^7}{7}\right)=\dfrac{9^7}{7}\pi=\\\\\\=\boxed{\dfrac{4782969}{7}\pi}

Answer B. or D.

(ii)

V=2\pi\cdot\int\limits_a^bx\cdot f(x)\, dx


V=2\pi\cdot\int\limits_0^{9}(x\cdot x^3)\, dx=2\pi\cdot\int\limits_0^{9}x^4\, dx=
2\pi\cdot\left[\dfrac{x^5}{5}\right]_0^9=2\pi\cdot\left(\dfrac{9^5}{5}-\dfrac{0^5}{5}\right)=\\\\\\=2\pi\cdot\dfrac{9^5}{5}=\boxed{\dfrac{118098}{5}\pi}

So we know that the correct answer is D.

(iii)
Line x = h

V=2\pi\cdot\int\limits_a^b(h-x)\cdot f(x)\, dx\qquad\implies\qquad h=18


V=2\pi\cdot\int\limits_0^9\big((18-x)\cdot x^3\big)\, dx=2\pi\cdot\int\limits_0^9(18x^3-x^4)\, dx=\\\\\\=2\pi\cdot\left(\int\limits_0^918x^3\, dx-\int\limits_0^9x^4\, dx\right)=2\pi\cdot\left(18\int\limits_0^9x^3\, dx-\int\limits_0^9x^4\, dx\right)=\\\\\\=2\pi\cdot\left(18\left[\dfrac{x^4}{4}\right]_0^9-\left[\dfrac{x^5}{5}\right]_0^9\right)=2\pi\cdot\Biggl(18\biggl(\dfrac{9^4}{4}-\dfrac{0^4}{4}\biggr)-\biggl(\dfrac{9^5}{5}-\dfrac{0^5}{5}\biggr)\Biggr)=\\\\\\

=2\pi\cdot\left(18\cdot\dfrac{9^4}{4}-\dfrac{9^5}{5}\right)=2\pi\cdot\dfrac{177147}{10}=\boxed{\dfrac{177147\pi}{5}}

Answer D. just as before.

6 0
3 years ago
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algol [13]

Answer:

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Step-by-step explanation:

4(g-1)=24

g-1=6

g=6+1

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