Answer:
Step-by-step explanation:
Given:
The above triangle
Required
Solve for AB in terms of a, b and angle C
Considering right angled triangle BOC where O is the point between b-x and x
From BOC, we have that:
Make h the subject:
Also, in BOC (Using Pythagoras)
Make the subject
Substitute for h
becomes
Factorize
In trigonometry:
So, we have that:
Take square roots of both sides
In triangle BOA, applying Pythagoras theorem, we have that:
Open bracket
Substitute and in
Open Bracket
Reorder
Factorize:
In trigonometry:
So, we have that:
Take square roots of both sides
Answer:
D would be your answer
Step-by-step explanation:
Answer:
The answer to your question is 2x² - 29x + 26
Step-by-step explanation:
dividend = 6x³ - 25x² + 20x + 4
divisor = 3x + 2
2x² - 29x + 26
3x + 2 6x³ - 25x² + 20x + 4
-6x³ - 4x²
0 - 29x² + 20x
+ 29x² + 58x
0 78x + 4
-78x - 52
0 - 48
quotient = 2x² - 29x + 26
remainder = -48
Result = 2x² - 29x + 26 - 48/6x³ - 25x² + 20x + 4
X is equal to 1
hope it helps