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andreev551 [17]
3 years ago
12

What is the value of 4 2/3 divided by 2/5

Mathematics
1 answer:
Nitella [24]3 years ago
6 0
4 2/3 /2 /5
14/3 / 2/5 cross multiply 
7/3 / 1/5 multiply 7 and 5 and 3 and 1
35/3 simplify
11 2/3
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4. Can two lines be parallel and perpendicular? Explain.
lidiya [134]

Answer: No

Step-by-step explanation: First, we need to understand that parallel lines are coplanar lines that do not intersect. On the other hand, perpendicular lines are lines that intersect at a right angle.

However, lines can't be both parallel and perpendicular because they either intersect each other at a right angle or never intersect.

So no, two lines can't be both parallel and perpendicular.

7 0
3 years ago
Simplify 3x^2y^4 x 2x^6y
Feliz [49]

Answer:

6x^8y^5

Step-by-step explanation:

(3)(2)= 6

add the exponents for the variables

8 0
3 years ago
The density of glass is 2.6 g/cm3 and the density of lead is 11.3 g/cm3. Does this mean there are more particles of lead in 1 cm
Colt1911 [192]
The answer is that there are more particles in 1 cubic cm. this is because within 1 cubic cm lead has 11.3g in compared to the 2.6 glass has. m/v= density. divide the masses over the volume and that will prove your answer.
8 0
3 years ago
A scale on a map shows that 2 inches = 25 miles.
Assoli18 [71]
Part A : 60miles would represent 4.8 inches
Part B : 1/4 inch would represent 3 and 1/8 miles

6 0
3 years ago
Read 2 more answers
a rectangular box with two sqaure opposite ends is to hold 8000 cubic inches. find the dimensions of the cheapest box if tge rec
AveGali [126]

Answer:

the dimensions of the box that minimizes the cost are 5 in x 40 in x 40 in

Step-by-step explanation:

since the box has a volume V

V= x*y*z = b=8000 in³

since y=z (square face)

V= x*y² = b=8000 in³

and the cost function is

cost = cost of the square faces *  area of square faces + cost of top and bottom * top and bottom areas + cost of the rectangular sides * area of the rectangular sides

C = a* 2*y² +  a* 2*x*y + 15*a* 2*x*y =  2*a* y² +  32*a*x*y

to find the optimum we can use Lagrange multipliers , then we have 3  simultaneous equations:

x*y*z = b

Cx - λ*Vx = 0 → 32*a*y -  λ*y² = 0 → y*( 32*a-λ*y) = 0 → y=32*a/λ

Cy - λ*Vy = 0  → (4*a*y + 32*a*x) - λ*2*x*y = 0

4*a*32/λ  + 32*a*x - λ*2*x*32*a/λ = 0

128*a² /λ +  32*a*x - 64*a*x = 0

32*a*x = 128*a² /λ

x  = 4*a/λ

x*y² = b

4*a/λ * (32*a/λ)² = b

(a/λ)³ *4096 =  8000 m³

(a/λ) = ∛ ( 8000 m³/4096 ) = 5/4 in

then

x  = 4*a/λ = 4*5/4 in = 5 in

y=32*a/λ = 32*5/4 in = 40 in

then the box has dimensions 5 in x 40 in x 40 in

3 0
3 years ago
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