Answer:
<em>Similar: First two shapes only</em>
Step-by-step explanation:
<u>Triangle Similarity Theorems
</u>
There are three triangle similarity theorems that specify under which conditions triangles are similar:
If two of the angles are congruent, the third angle is also congruent and the triangles are similar (AA theorem).
If the three sides are in the same proportion, the triangles are similar (SSS theorem).
If two sides are in the same proportion and the included angle is equal, the triangles are similar (SAS theorem).
The first pair of shapes are triangles that are both equilateral and therefore have all of its interior angles of 60°. The AAA theorem is valid and the triangles are similar.
The second pair of shapes are parallelograms. The lengths are in the proportion 6/4=1,5 and the widths are in proportion 3/2=1.5, thus the shapes are also similar.
The third pair of shapes are triangles whose interior acute angles are not congruent. These triangles are not similar
What table? You haven’t uploaded anything
(x+2y)(x-5y)
do foil method:
x^2-5xy+2xy-10y^2
simplify x^2-3xy-10y^2,
so d is correct.
Answer: 3
Step-by-step explanation:
Your question does not say what were your options, therefore I will answer generically: in order to understand if a point (ordered pair) is contained in a line, you need to substitute the x-component of the pair in the equation of the line and see if the calculations give you the y-component of the pair.
Example:
Your line is <span> y = 4/3x + 1/3
Let's see if <span>(0, 0) and (2, 3) </span>belong to this line
y</span> = <span>4/3·0 + 1/3 = 1/3 </span>≠ 0
Therefore, the line does not contain (0, 0)
y = 4/3·2 + 1/3 = 9/3 = 3
Therefore, the line contains (2, 3)
