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3 years ago

What examine the rotation. which best describes point D

Mathematics

1 answer:

zloy xaker [14]3 years ago

7 0

Answer:

center of rotation

Step-by-step explanation:

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Solve x divided by four equals eight . (1 point) 4 −4 32 −32

schepotkina [342]

X/4 = 8
multiply both sides by 4 to get the value of x
x=32

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2 years ago

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A rectangular carpet has a perimeter of 274 inches. The length of the carpet is 95 inches more than the width. What are the dime

GrogVix [38]

Answer:

Length: 116

Width: 21

Step-by-step explanation:

Let's say that the width of carpet is x. If the length of the carpet is 95 inches more than the width, then let's say that the width is x + 95.

Since we are solving for the perimeter, you have to multiply the width and the length(x and x + 95) by two.

So,

2x + 2x + 190 = 274.

Simplify this and you get:

4x= 274 - 190

4x = 84

x= 21

So, the width is 21. This means that the length is 21 + 95.

21 + 95 = 116

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2 years ago

Need help pronto! First to answer gets Brainliest!!!

Nostrana [21]

Answer:

Not sure if I correctly did it but Stan is 56$ and Kyle is 44$, unless they meant how much they spent and were left with.

Step-by-step explanation:

50 + 6 = 56

34 + 10 = 44

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1 year ago

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What is the right answer show your work

Snowcat [4.5K]

Quadratic is the answer.......................

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2 years ago

CALC- limits please show your method

gladu [14]

A. Factor the numerator as a difference of squares:

$\displaystyle\lim_{x\to9}\frac{x-9}{\sqrt x-3}=\lim_{x\to9}\frac{(\sqrt x-3)(\sqrt x+3)}{\sqrt x-3}=\lim_{x\to9}(\sqrt x+3)=6$

c. As $x\to\infty$ , the contribution of the terms of degree less than 2 becomes negligible, which means we can write

$\displaystyle\lim_{x\to\infty}\frac{4x^2-4x-8}{x^2-9}=\lim_{x\to\infty}\frac{4x^2}{x^2}=\lim_{x\to\infty}4=4$

e. Let's first rewrite the root terms with rational exponents:

$\displaystyle\lim_{x\to1}\frac{\sqrt[3]x-x}{\sqrt x-x}=\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}$

Next we rationalize the numerator and denominator. We do so by recalling

$(a-b)(a+b)=a^2-b^2$
$(a-b)(a^2+ab+b^2)=a^3-b^3$

In particular,

$(x^{1/3}-x)(x^{2/3}+x^{4/3}+x^2)=x-x^3$
$(x^{1/2}-x)(x^{1/2}+x)=x-x^2$

so we have

$\displaystyle\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}\cdot\frac{x^{2/3}+x^{4/3}+x^2}{x^{2/3}+x^{4/3}+x^2}\cdot\frac{x^{1/2}+x}{x^{1/2}+x}=\lim_{x\to1}\frac{x-x^3}{x-x^2}\cdot\frac{x^{1/2}+x}{x^{2/3}+x^{4/3}+x^2}$

For $x\neq0$ and $x\neq1$ , we can simplify the first term:

$\dfrac{x-x^3}{x-x^2}=\dfrac{x(1-x^2)}{x(1-x)}=\dfrac{x(1-x)(1+x)}{x(1-x)}=1+x$

So our limit becomes

$\displaystyle\lim_{x\to1}\frac{(1+x)(x^{1/2}+x)}{x^{2/3}+x^{4/3}+x^2}=\frac{(1+1)(1+1)}{1+1+1}=\frac43$

3 0

2 years ago

What examine the rotation. which best describes point D​

What examine the rotation. which best describes point D