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MrMuchimi
3 years ago
9

What examine the rotation. which best describes point D​

Mathematics
1 answer:
zloy xaker [14]3 years ago
7 0

Answer:

center of rotation

Step-by-step explanation:

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C: Rotation of 90 degrees. 
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The time college students spend on the internet follows a Normal distribution. At Johnson University, the mean time is 5 hrs wit
netineya [11]

Answer:

The probability that the average time 100 random students on campus will spend more than 5 hours on the internet is 0.5

Step-by-step explanation:

We are given that . At Johnson University, the mean time is 5 hrs with a standard deviation of 1.2 hrs.

Mean = \mu = 5 hours

Standard deviation = \sigma = 1.2 hours

We are supposed to find the probability that the average time 100 random students on campus will spend more than 5 hours on the internet i.e. P(X>5)

Z=\frac{x-\mu}{\sigma}

Z=\frac{5-5}{1.2}

Z=0

P(X>5)=1-P(X<5)=1-P(Z<0)=1-0.5=0.5

Hence the probability that the average time 100 random students on campus will spend more than 5 hours on the internet is 0.5

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3 years ago
The senior class plans a school trip to Washington DC. Students should bring money for meals and souvenirs. They are told to bri
Doss [256]
The answer is 200 dollars
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3 years ago
A 50-gal tank initially contains 20 gal of pure water. Salt- water solution containing 0.5 lb of salt for each gallon of water b
icang [17]

Answer:

x(15) = 21 lb

Step-by-step explanation:

Rate of change in volume of salt water solution = rate of volume incoming - rate of volume outgoing

                                dV/dt  = 4 - 2 =2gal/min

So, the equation for volume at cetain time t at given conditions and values becomes,

                                V(t) = 2t + V

                                V(t) = 2t + 20   gal-------------------euqation (1)

Rate of change in amount of salt = rate of salt in - rate of salt out

                                  dx/dt = {0.5*4} - {[x(t)/V(t)]*2}

                                  dx/dt = 2-2[(x(t))/(2t+20)]

                                  dx/dt = 2-[(x(t))/(v(t))] lb/min

Now, with integrating factor, we get

          exp[∫(1/(1+10))dt)] = t+10

the equation becomes

(t + 10)*x' + x = 2*(t+10)

((t+10)*x') = 2*(t+10)

(t+10)*x = t² + 20t + C

As x(0) = 0,

x(t) = (t²+20t)/(t+10)

x(15) = (15²+20*15)/(15+10)

x(15) = 21 lb

4 0
3 years ago
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