Point (10,2) perpendicular to y = 4x + 6

Write the equation of the line in slope intercept form

Ronch [10]

Y=mx+b is slope intercept form

5 0

4 years ago

Can someone plz help me find the answer to 2x=4 y-16. and 2x-y=-7

telo118 [61]

Answer:

So, y = 2x + 7;

Then, 2x = 4( 2x + 7 ) - 16;

2x = 8x + 28 - 16;

2x = 8x + 12;

- 6x = 12;

x = - 2;

Then, y = 2· (-2) + 7;

y = - 4 + 7;

y = 3.

Step-by-step explanation:

8 0

4 years ago

The graph of a square root function has a domain of (0, infinity) and range of [1, infinty). In two or more complete sentences,

KIM [24]

We know that Range of a function is the values that a function can take in its domain The range interval of a function is between the minimum value and the maximum value that the function can take so in this problem The range of the function is the interval-------> [1, ∞)

That means The minimum value of the function in the domain is The maximum value of the function in the domain is infinite

6 0

3 years ago

Find the surface area of this triangular prism. Be sure to include the correct unit in your answer.

Maru [420]

(19x15)+(19x20)+(19x25)+(15x20)= 1440cm²

5 0

4 years ago

The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price

inn [45]

Answer:

Product A has a greater percentage change in price.

Step-by-step explanation:

Part A:

The price f product A, f (x) after x years is given by:

$f(x) = 0.69\cdot(1.03)^{x}$

After x = 0 years, the price of product A is:

$f(0) = 0.69\cdot(1.03)^{0}=0.69$

After x = 1 years, the price of product A is:

$f(1) = 0.69\cdot(1.03)^{1}=0.69\cdot (1+0.03)=0.69\cdot (1+3\%)$

After 1 year, the price of product A is 3% times more than the original price.

This means that after one year, the new price is 103% of the original price, which means the price product A is increasing by 3%.

Again after x = 2 years, the price of product A is:

$f(2) = 0.69\cdot(1.03)^{2}=[0.69\cdot (1+3\%)]\times (1.03)$

This implies that after 2 years, the price of product A is 103% of the price after year 1.

This implies that the price of product A is 3% more than the previous year.

Thus, the price of product A is increasing each year by 3%.

Part B:

The data for Product B is as follows:

Time (t) Price [f (t)]

1 10,100

2 10,201

3 10,303.01

4 10,406.04

Product B is clearly increasing in price.

Consider the changes in price of Product B in the following intervals of years:

Year 1 - Year 2:

Price in year 1 = $10,100

Price in Year 2 = $10,201

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10201-10100}{10100}=0.01=1\%$

Year 2 - Year 3:

Price in Year 2 = $10,201

Price in year 3 = $10,303.01

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10303.01-10201}{10201}=0.01=1\%$

Year 3 - Year 4

Price in year 3 = $10,303.01

Price in Year 4 = $10,406.04

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10,406.04-10303.01}{10303.01}=0.09999\approx 0.01=1\%$

It is quite clear that the price of product B increases by 1% each year.

Thus, Product A has a greater percentage change in price.

3 0

3 years ago