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max2010maxim [7]
4 years ago
6

Can someone plz help me find the answer to 2x=4 y-16. and 2x-y=-7

Mathematics
1 answer:
telo118 [61]4 years ago
8 0

Answer:

So, y = 2x + 7;

Then, 2x = 4( 2x + 7 ) - 16;

2x = 8x + 28 - 16;

2x = 8x + 12;

- 6x = 12;

x = - 2;

Then, y = 2· (-2) + 7;

y = - 4 + 7;

y = 3.

Step-by-step explanation:


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PLEASE HELP ME on #57 WITH ALL WORK SHOWN!!<br><br> Tmr is my exam pls help...
-Dominant- [34]
<h3>Answer: x = 1/2</h3>

=========================================================

Explanation:

Recall that quadratic form is ax^2+bx+c.

So we need an x^2 term followed by an x term, then a constant at the end.

It may not look it, but the given equation is nearly in quadratic form.

Rewrite 9^(2x) as (9^x)^2

We get this equivalent equation (9^x)^2 - 2*(9^x) - 3 = 0

From here, let's make w = 9^x. Replace every copy of '9^x' with 'w' and we end up with this new simpler equation: w^2 - 2w - 3 = 0

From here we can use the quadratic formula or factor. I'll factor.

w^2 - 2w - 3 = 0

(w - 3)(w + 1) = 0

w-3 = 0 or w+1 = 0

w = 3 or w = -1

---------------------

Now we use these values of w to find x

If w = 3, then,

w = 9^x

3 = 9^x

log(3) = log(9^x)

log(3) = x*log(9)

x = log(3)/log(9)

x = log(3)/log(3^2)

x = log(3)/(2*log(3))

x = 1/2

At the last step, we have the log(3) terms cancel.

Repeat for w = -1

w = 9^x

-1 = 9^x

log(-1) = log(9^x)

We run into a problem. The log of any negative number is not a real number output. In other words, 9^x is never negative. Raising any positive number to a real number output leads the result to be positive. Take a look at the graph of y = 9^x to confirm this.

In short, w = -1 is extraneous so it doesn't lead to any x value solution.

So only w = 3 is useful.

Ultimately, the only solution is x = 1/2.

3 0
3 years ago
G(x)=x-7 if x equals 4
Vesna [10]

Answer:

g(4) = -3

Step-by-step explanation:

y = x - 7

y = 4 - 7    (substitute value for x)

y = -3        (solve)

7 0
3 years ago
Which numbers make a true statement when placed in the box?
sp2606 [1]
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6 0
3 years ago
Del dinero que tenia gaste 1/3 en comida y 1/8 en pasaje, quedándome aún 39 pesos ¿Cuanto tenia al principio?
BigorU [14]

Respuesta: 70 pesos

Explicación paso a paso:

Dado que:

Sea la cantidad total poseída = t

Fracción gastada en alimentos = 1/3 t = t / 3

Fracción gastada en pasaje = 1/8 t = t / 8

Monto restante después del gasto total = 39 pesos

Fracción total gastada:

(t / 3 + t / 8)

= (8t + 3t) / 24

= 11t / 24

Fracción restante después del gasto total:

(t - 11t / 24)

= 13t / 24

Por lo tanto,

Fracción restante después del gasto total = Cantidad restante después del gasto total

13t / 24 = 39

13t = 936

t = 936/13

t = 72 pesos

Por lo tanto,

Monto total poseído = 72 pesos

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3 years ago
Write a linear function f with f(0) =7 and f(3)=1
lisabon 2012 [21]

Answer:

f ( 1 ) = 2 , f ( 0 ) = -1

Step-by-step explanation:

3 0
4 years ago
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