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fomenos
3 years ago
9

Lisa has twelve fewer dimes than quarters, for a total of $11.05

Mathematics
1 answer:
SVEN [57.7K]3 years ago
5 0
So set up the equations
q-12=d
25q+10d=1105
plug in q-12 as d in the second equation:
25q+10q-120=1105, then simplify:
35q=1225
q=35
since there's 12 fewer dimes, we know that there's 23 dimes and 35 quarters.
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3^4 + 4 . 5 = _ (input whole numbers only.)
anygoal [31]
3^4=81
4*5=20
81+20=101
Hope this helped
6 0
3 years ago
Review the table of values for function h(x).
muminat

Answer:

a) The limit does not exist because the values of h(x) seem to oscillate between random values around x = 9.

Step-by-step explanation:

edg 21 ^u^

3 0
3 years ago
Read 2 more answers
Find an equation of a line with the x- and y-intercepts below. Use exact fractions when necessary.
tamaranim1 [39]

Answer:

y=\frac{5}{7}x-5

Step-by-step explanation:

All lines in the plane are of the form

y = mx+b

<u><em>The intersection with the Y-axis is obtained by replacing x with 0 </em></u>

<u><em>The intersection with the X-axis is obtained by replacing y with 0 </em></u>

If we want that the Y-intercept = -5, then  

-5 = m(0)+b

So b = -5

Our temporal equation is then

y = mx-5

If we want that the X-intercept = 7, then  

0 = m(7)-5

7m = 5

m = 5/7

So our final equation is

y=\frac{5}{7}x-5

Attached is the graph of the line

3 0
3 years ago
Which one of the following does not represent a proportional relationship?
Tamiku [17]

Answer:

may be these are your following

u forgot to right options that's why i am doing according to me

if these are wrong please tell me I will do according to your options

Step-by-step explanation:

in this 2 table does not repeat a proportional relationship

4 0
3 years ago
Solve for x.<br> 6(x - 1) = 9(x + 2)<br> x = -8<br> X = -3<br> X = 3<br> x = 8
Wewaii [24]

Answer:

x=-8

Step-by-step explanation:

6\left(x-1\right)=9\left(x+2\right)\\\mathrm{Expand\:}6\left(x-1\right):\quad 6x-6\\6\left(x-1\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac\\a=6,\:b=x,\:c=1\\=6x-6\cdot \:1\\\mathrm{Expand\:}9\left(x+2\right):\quad 9x+18\\9\left(x+2\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=9,\:b=x,\:c=2\\=9x+9\cdot \:2\\\mathrm{Multiply\:the\:numbers:}\:9\cdot \:2=18\\=9x+18\\6x-6=9x+18\\\mathrm{Add\:}6\mathrm{\:to\:both\:sides}

6x-6+6=9x+18+6\\Simplify\\6x=9x+24\\\mathrm{Subtract\:}9x\mathrm{\:from\:both\:sides}\\6x-9x=9x+24-9x\\Simplify\\-3x=24\\\mathrm{Divide\:both\:sides\:by\:}-3\\\frac{-3x}{-3}=\frac{24}{-3}\\Simplify\\\frac{-3x}{-3}=\frac{24}{-3}\\\mathrm{Simplify\:}\frac{-3x}{-3}:\quad x\\\frac{-3x}{-3}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}\\=\frac{3x}{3}\\\mathrm{Divide\:the\:numbers:}\:\frac{3}{3}=1\\=x\\\mathrm{Simplify\:}\frac{24}{-3}:\quad -8\\\frac{24}{-3}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}\\=-\frac{24}{3}\\\mathrm{Divide\:the\:numbers:}\:\frac{24}{3}=8\\=-8\\

4 0
3 years ago
Read 2 more answers
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