Answer:
The first graph best represent the given scenario.
Step-by-step explanation:
Given that Kent walked to the bus stop, then sat and waited until the bus arrived. He rode the bus for 25 minutes, then walked the last 3 blocks to work. we have to find which graph best represent the scenario.
In the first graph, it is given The line increases for 10 minutes means the distance as well as time increases i.e Kent walked for 10 minutes then, stays horizontal for 15 minutes means no distance covered i.e stop or wait for 15 minutes. After that graph increases rapidly for another 25 minutes, that means rode the bus for 25 minutes then increases slowly for 5 minutes indicate walked to work.
The above graph best represent the scenario.
All three option is analysed by graphing which doesn't show the above given scenario.
Answer:
Since every 30 days he wil have both lessons on the same day , and he already had both lessons on the last day of the previous month, that means that the day 30 the current month he wil have both lessons on the same day (It may be the last day if the month has 30 days or it may not be the last day if the month has 31 days)
Step-by-step explanation:
Lets find the least common factor of 5 and 6
Multiples of 5
5 10 15 20 35 30 35 40......
Multiples of 6
6 12 18 24 30 36
LCF of 5 and 6 = 30
Every 30 days he wil have both lessons on the same day
Answer:
5
Step-by-step explanation:
Because if you divide them all you see that in 5 you don't get a whole number
Answer:
Option A
Step-by-step explanation:
2x^2+10x+12
Divide through by 2
x^2 +5x+6=0
x^2 +3x+2x+6
x(x+3)+2(x+3)=0
(x+2)(x+3)=o
x=-2 or x=-3