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arlik [135]
4 years ago
15

Decompose the fraction 5/6 into three fractions with three different numerators. Is this possible?

Mathematics
1 answer:
Lemur [1.5K]4 years ago
6 0
I think the answer is 0/6, 2/6, 3/6. Or 0/6, 1/6, 4/6. But if 0/6 isn't allowed, then it is not possible.
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3y-y please can you work it out
AnnyKZ [126]
The two y’s are like term so it is possible to subtract. So 3y-y=2y
8 0
3 years ago
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If you multiply the slopes of two perpendicular lines, the product is -1.
ki77a [65]

$-\frac{1}{2}\cdot2=-1

Slope of the line h is 2.

The equation for line h is y = 2x + 4.

Solution:

General equation of a line is y = mx + c,

where m is the slope of the line and c is the y-intercept.

In the given image, line g and line h are intersecting lines and perpendicular to each other.

Equation of line g is y=-\frac{1}{2} x+2.

Slope of the line g (m_1) = -\frac{1}{2}

If two lines are perpendicular, then the product of the slopes is –1.

⇒ m_1 \cdot m_2=-1

<u>To find the slope of the line h:</u>

$\Rightarrow-\frac{1}{2}  \cdot m_2=-1

$\Rightarrow  m_2=-1 \times(-2)

$\Rightarrow m_2=2

Slope of the line h is 2.

<u>To find the equation of a line h:</u>

Line h passing through the point (0, 4) and slope 2.

Point-slope formula:

\left(y-y_{1}\right)=m\left(x-x_{1}\right)

\left(y-4)=2\left(x-0\right)

y-4=2x

y=2x+4

The equation for line h is y = 2x + 4.

5 0
3 years ago
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[-8,6]. B=[
just olya [345]

Answer:

49°

Step-by-step explanation:

Given vectors:

a = [-8, 6]

B = [√7, 3]

θ = ?

To find the angle between the two vectors, we will be using the formula,

                                   a.B = |a||B|cosθ

For simplicity, it is good to first calculate the dot product, and the magnitudes. Then we will substitute the values of the dot product, and the magnitudes of the vectors to solve for the angle.

Calculating the dot product

         a.B = (-8, 6) . (√7, 3)

               = (-8 × √7) + (6 × 3)

               = -8√7 + 18

               = 18 - 8√7

               = 10√7

Calculating the magnitude the vectors

1. The magnitude of vector (-8, 6)    

                |a| = \sqrt{(-8)^{2} + 6^{2}}

                |a| = \sqrt{64 + 36}

                |a| = \sqrt{100}

                |a| = 10

2. The magnitude of vector (√7, 3)

                |B| = \sqrt{(\sqrt{7})^{2} + 3^{2}}

                |B| = \sqrt{7 + 9}

                |B| = \sqrt{16}

                |B| = 4

Calculating the angle between the vectors,

                cosθ = \frac{a.B}{|a||B|}

                cosθ = \frac{10\sqrt{7}}{10 * 4}

                cosθ = 0.6614

                θ = cos⁻¹0.6614

                θ = 48.59°

                θ = 49°

5 0
4 years ago
What's 5 5/6 as a improper fraction
yawa3891 [41]
Answer: 35/6
Work: 5*6=30
30+5=35
35/6
7 0
4 years ago
The volume of a cone is 225 cubic inches. The diameter is 15 inches. What is the height of the cone?
mrs_skeptik [129]

its answer is No.C {4 inches}

4 0
3 years ago
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