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Jlenok [28]
3 years ago
13

What is the inverse of the function f(x)=19/x^3

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
5 0
step 1: replace f(x) with y ⇒ y=\frac{19}{ x^{3} }

step 2: switch the x and y ⇒ x=\frac{19}{ y^{3} }

step 3: solve for y using algebra ⇒ xy^{3} =19 ⇒ y^{3}= \frac{19}{x} ⇒ y= \sqrt[3]{ \frac{19}{x} }

step 4: switch y to f ^{-1}(x)  and this known as "the inverse of f(x) 
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Keep in mind that the first piece y = x^2-4 is only graphed when x = 2 or larger, so we ignore x = -2. This is one x intercept, but there may be more. Let's check the other graph to see what we get.

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Set the second piece equal to zero and solve for x

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We get the same result as above in the prior section. Because of this, the two pieces connect at this junction point.

The x intercept x = 2 leads to the location (2,0). The x intercept always occurs when y = 0.

The graph below shows this.

side note: the red piece y = x^2 - 4 looks linear, but it's actually not a straight line. It's just a really stretched out curve.

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