3 years ago

Pls HELP, WILL GAVE A 5 STAR RATING AND BRAINLIEST

Mathematics

1 answer:

bonufazy [111]3 years ago

6 0

Answer:

Step-by-step explanation:

-7x-3=2-7x-5

cancel equal terms

-3=2-5

calculate the difference

-3= -3

This statement is true.

You might be interested in

If f(x) = 3x^2 - 4 and g(x) = x+2, find (f - g)(x).

galina1969 [7]

Answer:

3x^2-x-6

Step-by-step explanation:

f(x) = 3x^2 - 4

g(x) = x+2

(f - g)(x)= 3x^2 - 4-( x+2)

Distribute the minus sign

(f - g)(x)= 3x^2 - 4- x-2

Combine like terms

= 3x^2-x-6

8 0

3 years ago

Read 2 more answers

Which of the following shows a correct solution process for │ x + 8│- 5= 2?

Vilka [71]

X1=-15
X2=-1
I think this is the answer

3 0

2 years ago

Read 2 more answers

Please help with questions 7-10! I have to turn it in soon and I’m so lost!

Arisa [49]

Answer:

7)c

8)d

9)b

10)a

Step-by-step explanation:

3 0

3 years ago

If cos Θ = negative 4 over 7, what are the values of sin Θ and tan Θ? (2 points)

seropon [69]

I accept that θ in second quadrant, therefore sinθ > 0, cosθ < 0 and tanθ < 0.

$\cos\theta=-\dfrac{4}{7}\\\\We\ know:\sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x\to\sin x=\sqrt{1-\cos^2x}\\\\subtitute:\\\\\sin x=\sqrt{1-\left(-\dfrac{4}{7}\right)^2}=\sqrt{1-\dfrac{16}{49}}=\sqrt{\dfrac{33}{49}}=\dfrac{\sqrt{33}}{7}$

$We\ know:\tan x=\dfrac{\sin x}{\cos x}\\\\subtitute:\\\\\tan x=\dfrac{\sqrt{33}}{7}:\left(-\dfrac{4}{7}\right)=-\dfrac{\sqrt{33}}{7}\cdot\dfrac{7}{4}=-\dfrac{\sqrt{33}}{4}$

5 0

3 years ago

Alice and Bob each picks an integer number uniformly at random between 1 and n. Assume that all possible combinations of two num

kotegsom [21]

Answer:

(n-1)/2n

Step-by-step explanation:

½(1 - 1/n)

(n-1)/2n

7 0

3 years ago