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3 years ago

Need help i don't understand

Mathematics

1 answer:

yKpoI14uk [10]3 years ago

6 0

The second one brother

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The product of two consecutive integers is 90. Which equation can be used to find the two integers?

joja [24]

Two consecutive integers would be x and x+ 1
if you multiply them you have x(x + 1) = x^2 + x
if you want the product to equal 90 you get x^2 + x = 90
The first option is correct.

3 0

3 years ago

A student receives test scores of 62, 83, and 91. This student's term project score is 88. Each test is worth 20% of the final g

miskamm [114]

Answer:

The student's current average score will be 69.2

Step-by-step explanation:

Let first test be TEST A: which is 20 of total and secures 62

Let second test be TEST B: which is 20 of the total marks and has secured 83.

Let third test be TEST C: which is 20 of total and has secured 91.

And now the TEST D which is 25 of total and has secured 88.

Therefore, by multipying across

${0.2}\times{62}$ = 12.4

${0.2}\times{83}$ = 16.6

${0.2}\times{91}$ = 18.2

${0.25}\times{88}$ =22

Now, by adding the scores to get the average score

We get, 69.2.

6 0

3 years ago

Find m<1 and find m<2

xenn [34]

Answer:

m∠1 = 50°

m∠2 = 130°

Explanation:

m∠2 = 130° because of alternate exterior angles.

m∠1 = 50° because it is supplementary to m∠2. So, 180 - 130 = 50.

8 0

3 years ago

What is 9/7 times -9/5?

pochemuha

Answer:

- 2 11/35

Step-by-step explanation:

Step 1:

9/7 × - 9/5 Equation

Step 2:

- 81/35 Multiply

Answer:

- 2 11/35 Convert

Hope This Helps :)

8 0

3 years ago

In a lab, a scientist is growing bacteria for a study. The scientist begins with a bacteria

Diano4ka-milaya [45]

Answer:

The answer is below

Step-by-step explanation:

The growth of the bacteria is in the form of an exponential growth. It is given by the formula:

$P(t)=ae^{rt}\\\\where\ t\ is\ the\ number\ of \ hours, P(t)\ is\ the \ population\ at\ t\ hours\\\and\ a=population\ at\ start$

At 2 hours, the population is 62 cells, hence:

$P(2)=ae^{2r}\\\\62=ae^{2r}\ \ .\ \ .\ \ .\ (1)$

After another 2 hours (4 hours), the population is 1 million:

$P(4)=ae^{4r}\\\\1000000=ae^{4r}\ \ .\ \ .\ \ .\ (2)\\\\Divide \ equation\ 2\ by\ equation\ 1:\\\\\frac{1000000}{62}=\frac{ae^{4r}}{ae^{2r}} \\\\16129=e^{2r}\\\\ln(e^{2r})=ln(16129)\\\\2r=9.688\\\\r=4.844$

Put r = 4.844 in equation 1

$62=ae^{2*4.844}\\\\62=16129a\\\\a=0.003844$

$P(t)=0.003844e^{4.844t}\\\\at \ start,t=0\\\\P(0)=0.003844$

4 0

3 years ago