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weeeeeb [17]
2 years ago
15

If h(x) = 5 x and k (x) = startfraction 1 over x endfraction, which expression is equivalent to (k circle h) (x)?

Mathematics
1 answer:
Triss [41]2 years ago
5 0

The equivalent expression to (k o h)(x)is \frac{1}{5 + x}

Therefore  (k o h)(x) = \frac{1}{5 + x}

Given that the functions h is defined by h(x)=5+x

and k is defined by k (x) = \frac{1}{x}

To find the composition of k and h that is: (k o h) (x)

Therefore

k (h(x)) = k (5+x)

k (h(x)) = \frac{1}{5+  x}

The equivalent expression to is \frac{1}{5+  x}

<h3>What is expression?</h3>
  • An expression, often known as a mathematical expression, is a finite collection of symbols that are well-formed in accordance with context-dependent principles.
  • Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.
  • Expressions are syntactic devices. It must be properly constituted, which means that the permissible operators must have the right amount of inputs in the right places, legal characters for these inputs, a clearly defined order of operations, etc.
  • The syntax requirements must be followed for a string of symbols to be considered a valid mathematical expression.

To learn more about Expression with the given link

brainly.com/question/14083225

#SPJ4

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It looks like you want to compute the double integral

\displaystyle \iint_D (x+y) \,\mathrm dx\,\mathrm dy

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Convert to polar coordinates, in which <em>D</em> is given by the set

<em>D</em> = {(<em>r</em>, <em>θ</em>) : 0 ≤ <em>r</em> ≤ 1 and 0 ≤ <em>θ</em> ≤ 2<em>π</em>}

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<em>x</em> = <em>r</em> cos(<em>θ</em>)

<em>y</em> = <em>r</em> sin(<em>θ</em>)

d<em>x</em> d<em>y</em> = <em>r</em> d<em>r</em> d<em>θ</em>

Then the integral is

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