Answer:
a) 4(t - r) = 4(6 - 2.5) = 4 x 3.5 = 14
b) 4t - r = (4 x 6) - 2.5 = 24 - 2.5 = 21.5
c) 2(3t - 10) = 2(3 x 6 - 10) = 2(18 - 10) = 2 x 8 = 16
d) (t - 2)² = (6 - 2)² = 4² = 4 x 4 = 16
e) cannot decipher the equation
f) 6r + t = 6 x 2.5 + 6 = 15 + 6 = 21
A negative times a negative is a positive. I am not sure if that's the question, but hopefully that helps if it was.
Given :
The diagonals of rhombus ABCD intersect at E.
∠CAD = 20°.
To Find :
The angle ∠CDA.
Solution :
We know, diagonals of a rhombus bisects each other perpendicularly.
So, ∠DEA = 90°.
In triangle ΔEAD :
∠EAD + ∠AED + ∠EDA = 180°
20° + 90° + ∠EDA = 180°
∠EDA = 70°
Now, we know diagonal of rhombus also bisect the angle between two sides .
So, ∠CDA = 2∠EDA
∠CDA = 2×70°
∠CDA =140°
Therefore, ∠CDA is 140°.
Answer:
surface area = 245.04 cm² (nearest tenth)
Step-by-step explanation:
Surface area of a closed cylinder = 
Given:
- diameter = 6 cm ⇒ radius = 3 cm
- height = 10 cm
⇒ surface area = 2 × 
× 3² + 2 × × 3 × 10
= 78
= 245.04 cm² (nearest tenth)
Answer:
Decompose the figure into two rectangles and add the areas.
Find the area of the entire rectangle and of the removed corner and subtract the areas.
Decompose the figure into three rectangles and add the areas.
Step-by-step explanation:
With all of these you can actually calculate the area of the composite figure, some of them are more easy and efficient than the other, for example dividing the composite area into three rectangles is not very efficient but will do the job, and the one where you decompose the area into two rectangles would be the best one, as well as the one where you find the area of the larger rectangle and the subtract from that the rectangle that is taken off in the right corner.
