3 years ago

Tell whether the triangles are similar. Yes or No

Mathematics

1 answer:

horrorfan [7]3 years ago

3 0

Answer:

no. they are not. add up the angles on each triangle to find x, if the angles are not exactly the same, then they are not similar

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Use a double angle identity to rewrite the formula r(Θ)=<img src="https://tex.z-dn.net/?f=1%2F16v%5E2sin%28theta%29cos%28theta%2

Artist 52 [7]

Answer:

1/32v²sin2θ

Step-by-step explanation:

Given the expression r(theta) = 1/16v²sinθcosθ

According to double angle of trigonometry identity;

Sin2θ = sin(θ+θ)

Sin2θ = sinθcosθ + cosθsinθ

Sin2θ = 2sinθcosθ

sinθcosθ = sin2θ/2 ... **

Substituting equation ** into the question

1/16v²sinθcosθ = 1/16v²(sin2θ/2)

1/16v²sinθcosθ = 1/2×1/16v²(sin2θ)

1/16v²sinθcosθ = 1/32v²sin2θ

Hence using the double angle identity, the equivalent expression is 1/32v²sin2θ

7 0

3 years ago

What is 25 1/2 divided by 6 1/4

Kisachek [45]

4.08, or 4 2/25 :) hope this helps

6 0

3 years ago

Read 2 more answers

$35,125 loan, a feat which took ten years of quarterly payments. The loan had an interest rate of 7.44%, compounded quarterly. I

Darya [45]

First find the amount of each payment:
$35,125 = P(\frac{(1+i)^{40} -1}{i (1+i)^{40}}) , i = \frac{.0744}{4} \\ \\ P = 1252.70$

The total cost will be 40 payments plus service charges.
$40*1252.70 + 5180.70 = 55,288.90$

The percentage is the service charge divided by total cost:
$X = \frac{5180.70}{ 55,288.90} = .0937 = 9.37\%$