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Aleksandr [31]
3 years ago
6

How to solve square roots

Mathematics
1 answer:
Arada [10]3 years ago
6 0

Answer: √16=4

√100=10

√36=6

√64=8

√1=1

√81=9

√25=5

√9=3

√4=2

Step-by-step explanation:

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What is the slope of the line that passes through the points (-9, -8)((−15,−16)? Write your answer in simplest form.
alexandr402 [8]

Answer:

Therefore the slope of the line that passes through the points (-9, -8),(−15,−16) is

Slope=\dfrac{4}{3}

Step-by-step explanation:

Given:

Let,

point A( x₁ , y₁) ≡ ( -9 ,-8)

point B( x₂ , y₂ )≡ (-15 ,-16)

To Find:  

Slope = ?

Solution:

Slope of Line Segment AB is given as

Slope(AB)=\dfrac{y_{2}-y_{1} }{x_{2}-x_{1} }

Substituting the values we get

Slope(AB)=\dfrac{-16-(-8)}{-15-(-9)}\\\\Slope(AB)=\dfrac{-16+8}{-15+9}\\\\Slope(AB)=\dfrac{-8}{-6}=\dfrac{4}{3}

Therefore the slope of the line that passes through the points (-9, -8),(−15,−16) is

Slope(AB)=\dfrac{4}{3}

4 0
3 years ago
Solve the inequality below<br> -8x + 4 &gt; 20<br> Include x and number in answer
Genrish500 [490]

Answer:

x<-2

Step-by-step explanation:

You first subtract 4 from both sides. Then you divide both sides by -8 (note: when you multiply or divide by a negative the sign flips. Then you get your answer

7 0
3 years ago
PLEASE HELP ME NOW!!!! 100 POINTS!!!
blondinia [14]

Answer: 12 balls i think

3 0
3 years ago
Read 2 more answers
A dog is leashed to the corner of a house with a 20 ft long leash. How much running area does the dog have? Round your answer to
11111nata11111 [884]

Answer:

The dog's running area is approximately 942 feet².

Step-by-step explanation:

The dog is leashed to a fixed point, the leash has a length of 20 ft, therefore he can rotate around that point at the maximum distance equal to the length of the leash. This pattern forms a circle, but there is an obstruction, which is the corner of the house. This obstruction takes an arc of the original circle, so the running area of the dog is the area of the whole circle minus the area of the arc formed by the corner of the house.

\text{dog's area} = \text{circle's area} - \text{arc's area}\\\\\text{dog's area} = pi*(20^2) - \frac{90}{360}*pi*(20^2)\\\\\text{dog's area} = \frac{270}{360}*pi*(400)\\\\\text{dog's area} = 942.477\text{ feet}^2

The dog's running area is approximately 942 feet².

3 0
3 years ago
Help plz!! The function h(t)=-16t^2+22t+4 models the height (h) of a football t seconds after it is thrown. The question ask to
Black_prince [1.1K]
If you're familiar with the quadratic equation
\frac{ -b \pm \sqrt{b^2-4ac}}{2a}

well, \frac{ -b}{2a} is the x component of the vertex, in your case, the vertex is the highest point

figure out what t is at the highest point, and then substitute that back into the equation in order to determine height

x=t in this problem
8 0
3 years ago
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