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2 years ago

Find the area of rectangle PLUM

Mathematics

1 answer:

Cerrena [4.2K]2 years ago

7 0

PL= sqrt(4^2+12^2)=4sqrt(1+9)=4sqrt(10)

Using similarity gives that AM=4/3.

ML=40/3

[PLMU]=40/3 * 4 = 160/3 (53.33)

PM= sqrt(4^2+16/9)=sqrt(160/9)=4sqrt(10)/3

4sqrt(10)*4sqrt(10)/3=160/3 or approximately 53.33

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Find the constant of variation for the relation and use it to write an equation for the statement. Then solve the equation.

hammer [34]

Answer: option d.

Step-by-step explanation:

If y varies directly as x and z, the form of the equation is:

$y=kxz$

Where k is the constant of variation.

If y=4 when x=6 and z=1 then substitute these values into the expression and solve for k:

$4=k(6)(1)\\4=6k\\k=\frac{4}{6}\\\\k=\frac{2}{3}$

Substitute the value of k into the expression. Then, the equation is:

$y=\frac{2}{3}xz$

To find the value of y when x=7 and z=4, you must substute these values into the equation. Therefore you obtain:

$y=k=\frac{2}{3}(7)(4)$

$y(7,4)=\frac{56}{3}$

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2 years ago

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Which is the midpoint of the segment joining (12, 2) and (-5, – 7)?

Rainbow [258]

Answer:

$m(x, y)=(\frac{7}{2} , -\frac{5}{2} )$

Step-by-step explanation:

Midpoint of line segment is calculated as

$m(x, y)=(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2} )$ -----------(1)

Here

$(x_1, y_1) = (12,2) \ \ and \ \ (x_2, y_2) = (-5, -7)$

Substituting values in equation (1)

$m(x, y)=(\frac{12-5}{2} , \frac{2-7}{2} )$

$m(x, y)=(\frac{7}{2} , -\frac{5}{2} )$

3 0

2 years ago

What’s the measure of the angle theta?

11111nata11111 [884]

Answer:

∅ = 50°

Step-by-step explanation:

YOU NEED A CALCULATOR TO SOLVE THIS!

You need to use Law of Sines

$\frac{a}{sinA} =\frac{b}{sinB} = \frac{c}{sinC}$

Here you will be doing $\frac{a}{sinA} =\frac{c}{sinC}$

a and c are the lengths, while A and C are the angles

$\frac{3.46}{sinA} = \frac{2.54}{sin43}$ you want to get the denominators out from underneath so multiply both sides by sinA and sin43

$3.46sin43 = 2.54sinA$

Now you want to get sinA alone so divide both sides by 2.54

$\frac{3.46sin43}{2.54} = sinA$ now get A alone

$sin^{-1} (\frac{3.46sin43}{2.54}) = A$ put that into the calculator

$49.61741033 = A$

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2 years ago

The circumference of circle x in which a = 49pi in squared

zzz [600]

Answer:

C = 14 pi inches

Step-by-step explanation:

The area of a circle is given by

A = pi r^2

49 pi = pi r^2

Divide each side by pi

49 pi/pi = pi /pi r^2

49 = r^2

Take the square root of each side

7 = r

The circumference is given by

C = 2 * pi *r

C = 2 * pi *7

C = 14 pi inches

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3 years ago

The Wall Street Journal reported that Walmart Stores Inc. is planning to lay off 2300 employees at its Sam's Club warehouse unit

Advocard [28]

Answer:

(a) The mean is 52 and the median is 55.

(b) The first quartile is 44 and the third quartile is 60.

(d) The variance is 100.143 and the standard deviation is 10.01.

(e) There are no outliers in the data set.

(f) Yes

Step-by-step explanation:

The data provided is:

S = {55, 56, 44, 43, 44, 56, 60, 62, 57, 45, 36, 38, 50, 69, 65}

(a)

Compute the mean of the data as follows:

$\bar x=\frac{1}{n}\sum x\\=\frac{1}{15}[55+ 56+ 44+ 43+ 44+ 56+ 60+ 62+ 57+ 45 +36 +38 +50 +69+ 65]\\=\frac{780}{15}\\=52$

Thus, the mean is 52.

The median for odd set of values is the computed using the formula:

$Median=(\frac{n+1}{2})^{th}\ obs.$

Arrange the data set in ascending order as follows:

36, 38, 43, 44, 44, 45, 50, 55, 56, 56, 57, 60, 62, 65, 69

There are 15 values in the set.

Compute the median value as follows:

$Median=(\frac{15+1}{2})^{th}\ obs.=(\frac{16}{2})^{th}\ obs.=8^{th}\ observation$

The 8th observation is, 55.

Thus, the median is 55.

(b)

The first quartile is the middle value of the upper-half of the data set.

The upper-half of the data set is:

36, 38, 43, 44, 44, 45, 50

The middle value of the data set is 44.

Thus, the first quartile is 44.

The third quartile is the middle value of the lower-half of the data set.

The upper-half of the data set is:

56, 56, 57, 60, 62, 65, 69

The middle value of the data set is 60.

Thus, the third quartile is 60.

(c)

The range of a data set is the difference between the maximum and minimum value.

Maximum = 69

Minimum = 36

Compute the value of Range as follows:

$Range =Maximum-Minimum\\=69-36\\=33$

Thus, the value of range is 33.

The inter-quartile range is the difference between the first and third quartile value.

Compute the value of IQR as follows:

$IQR=Q_{3}-Q_{1}\\=60-44\\=16$

Thus, the inter-quartile range is 16.

(d)

Compute the variance of the data set as follows:

$s^{2}=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=\frac{1}{15-1}[(55-52)^{2}+(56-52)^{2}+...+(65-52)^{2}]\\=100.143$

Thus, the variance is 100.143.

Compute the value of standard deviation as follows:

$s=\sqrt{s^{2}}=\sqrt{100.143}=10.01$

Thus, the standard deviation is 10.01.

(e)

An outlier is a data value that is different from the remaining values.

An outlier is a value that lies below 1.5 IQR of the first quartile or above 1.5 IQR of the third quartile.

Compute the value of Q₁ - 1.5 IQR as follows:

$Q_{1}-1.5QR=44-1.5\times 16=20$

Compute the value of Q₃ + 1.5 IQR as follows:

$Q_{3}+1.5QR=60-1.5\times 16=80$

The minimum value is 36 and the maximum is 69.

None of the values is less than 20 or more than 80.

Thus, there are no outliers in the data set.

(f)

Yes, the data provided indicates that the Walmart is meeting its goal for reducing the number of hourly employees

6 0

2 years ago