A large city in the ancient world was square-shaped. measured in miles, its area numerically exceeded its perimeter by about 132
. find its dimensions. (round to the nearest tenth.
1 answer:
Area = perimeter + 132.
Let each side of the city be x miles long, then:-
x^2 = 4x + 132
x^2 - 4x - 132 = 0
x = [-(-4) +/- sqrt((-4)^2 - 4 * 1 *-132)] / 2
x = 13.66, -9.66 We ignore the negative
So the city has dimension of 13.66 * 13.66
13.7 * 13.7 to nearest 10th
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Christine crawled:
3 ft* (3/4)= 2.25 ft.
3 ft+ 2.25 ft= 5.25 ft
We already know that 1 ft= 12 in.
5.25 ft* (12in/ 1 ft)= 63 in.
The total distance the two children crawled together is 63 in~
Answer: 50
Find the area of the triangles then multiply by 2.
1/2 x 5 x 10 = 25
25 x 2 = 50
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Answer:
$2266
Step-by-step explanation:
Ⓗⓘ ⓣⓗⓔⓡⓔ
Well, 3% of $2200 is $66
$2200+$66=$2266
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