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diamong [38]
3 years ago
10

PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Andrew [12]3 years ago
4 0

Answer: Im trying to figure out the same question.

Step-by-step explanation:

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Silly question I know but lets see who can answer faster <br> Q: 2+2
777dan777 [17]

Answer:

22 is the answer

Step-by-step explanation:

22 is the answer

5 0
2 years ago
Read 2 more answers
Solve for x: 3/4x+5/8=4x
kompoz [17]
So, you have 3/4x + 5/8 = 4x. We can do this in two ways. Since fractions are harder to deal with, we can turn the fractions into whole numbers.

First we need to find the LCD (Least Common Denominator) between 4 and 8, which is 8. So multiply the 3/4x by 2/2, which gives you an equivalent fraction of 6/8x.

So now we have 6/8x + 5/8 = 4x. Now multiply both sides by 8, to get rid of the denominators of the fractions. That gives us 6x + 5 = 32x. Now use the subtraction property of equality to subtract 6x from both sides giving us 5 = 26x. 

Now you can use the division property of equality to divide 26 on both sides, which gives us x = 5/26.

Hope this helps. :D Feel free to ask any other questions, and if you have any questions about my explanation, don't hesitate to ask.
6 0
3 years ago
A rectangle has length 72 cm and width 56 cm. The other rectangle has the same area as this one, but its width is 21 cm. What is
Ira Lisetskai [31]

The length of the rectangle is = 72 cm

The width of the rectangle is = 56 cm

Area of the rectangle is = length*width

= 72\times56=4032 cm²

As given, the other rectangle has the same area as this one, but its width is 21 cm.

Let the length here be = x

4032=x*21

x=\frac{4032}{21}=192

Hence, length is 192 cm.

We can see that as width decreases, the length increases if area is constant and when length decreases then width increases if area is constant.

So, in the new rectangle,constant of variation=k is given by,

\frac{192}{72}=\frac{8}{3} or \frac{56}{21}=\frac{8}{3}

Hence, the constant of variation is \frac{8}{3}

7 0
2 years ago
In a class of 27 students, five students have 1 pet.
Digiron [165]

Answer:

yes, the student who has 8 pets.

Step-by-step explanation:

the majority of the class has between 0-4 pets leaving the student with 8 to be the "outlier"

3 0
3 years ago
Read 2 more answers
Simplify<br> 1/2 + 2/3 x 1 1/3
Blizzard [7]
My work to your question
6 0
3 years ago
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