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Nutka1998 [239]
3 years ago
12

Alice has 1/6 of a box of cereal. Alice and her brother want to split the cereal equally. Which expression represents the fracti

on of the box of cereal that Alice gets?
Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
8 0

\frac{1}{6}   \div 2 = \frac{1}{6}  \times  \frac{1}{2}  =  \frac{1}{12}
vova2212 [387]3 years ago
4 0

Answer:

\frac{1}{6}\div 2

Step-by-step explanation:

We have been given that Alice has 1/6 of a box of cereal. Alice and her brother want to split the cereal equally.

Since there are two persons, who wants to divide 1/6 of a box of cereal, so we will divide total amount of cereal by 2 to find amount that each person would get.

\frac{1}{6}\div 2

\frac{1}{6}\times\frac{1}{2}

\frac{1}{12}

Therefore, Alice will get \frac{1}{12} of the cereal and expression \frac{1}{6}\div 2 represents this situation.

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Step-by-step explanation:

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-7(v + 5) = 35 help
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3 years ago
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A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 29 ft/s. Its height
Ilia_Sergeevich [38]

Answer:

\overline{v}_{@\Delta t=0.01s}=-15.22ft/s, \overline{v}_{@\Delta t=0.005s}=-15.11ft/s, \overline{v}_{@\Delta t=0.002s}=-15.044ft/s, \overline{v}_{@\Delta t=0.001s}=-15.022ft/s

Step-by-step explanation:

Now, in order to solve this problem, we need to use the average velocity formula:

\overline{v}=\frac{y_{f}-y_{0}}{t_{f}-t_{0}}

From this point on, you have two possibilities, either you find each individual y_{f}, y_{0}, t_{f}, t_{0} and input them into the formula, or you find a formula you can use to directly input the change of times. I'll take the second approach.

We know that:

t_{f}-t_{0}=\Delta t

and we also know that:

t_{f}=t_{0}+\Delta t

in order to find the final position, we can substitute this final time into the function, so we get:

y_{f}=29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}

so we can rewrite our formula as:

\overline{v}=\frac{29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}-y_{0}}{\Delta t}

y_{0} will always be the same, so we can start by calculating that, we take the provided function ans evaluate it for t=1s, so we get:

y_{0}=29t-22t^{2}

y_{0}=29(1)-22(1)^{2}

y_{0}=7ft

we can substitute it into our average velocity equation:

\overline{v}=\frac{29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}-7}{\Delta t}

and we also know that the initil time will always be 1, so we can substitute it as well.

\overline{v}=\frac{29(1+\Delta t)-22(1+\Delta t)^{2}-7}{\Delta t}

so we can now simplify our formula by expanding the numerator:

\overline{v}=\frac{29+29\Delta t-22(1+2\Delta t+\Delta t^{2})-7}{\Delta t}

\overline{v}=\frac{29+29\Delta t-22-44\Delta t-22\Delta t^{2}-7}{\Delta t}

we can now simplify this to:

\overline{v}=\frac{-15\Delta t-22\Delta t^{2}}{\Delta t}

Now we can factor Δt to get:

\overline{v}=\frac{\Delta t(-15-22\Delta t)}{\Delta t}

and simplify

\overline{v}=-15-22\Delta t

Which is the equation that will represent the average speed of the ball. So now we can substitute each period into our equation so we get:

\overline{v}_{@\Delta t=0.01s}=-15-22(0.01)=-15.22ft/s

\overline{v}_{@\Delta t=0.005s}=-15-22(0.005)=-15.11ft/s

\overline{v}_{@\Delta t=0.002s}=-15-22(0.002)=-15.044ft/s

\overline{v}_{@\Delta t=0.001s}=-15-22(0.001)=-15.022ft/s

5 0
3 years ago
If Gerrard knows that △WXV≅△UXT, how can Gerrard prove that quadrilateral TUVW is a parallelogram?
mina [271]

Answer:

Second Choice

3 0
4 years ago
I need help! 30 points! Will mark brainliest! I'm giving up my rank for this answer! Please!
Sedaia [141]

Answer: a = -3

Step-by-step explanation: First we distribute the -2 to a and -3 to get -2a+6=12, then subtract 6 on both sides, -2a=6, finally divide by -2 on each side to get a = -3.

Hope this helps!

Please consider marking BRAINLIEST!

5 0
3 years ago
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