All categories

2 years ago

What is the domain of the relation y = arccscx?

Mathematics

1 answer:

Stella [2.4K]2 years ago

5 0

Answer:

$y=arc\csc x$

Step-by-step explanation:

The given function is $y=arc\csc x$ .

The domain refers to all values of x for which this function is defined.

Recall that: the domain of $y=arc \sin (x)$ is $-1\le x\le1$

And we know $y=arc\csc x$ is the reciprocal of $y=arc \sin (x)$ .

Therefore the complement of the domain of $y=arc \sin (x)$ which is $(-\infty,-1]\cup [1,+\infty)$ is the domain of $y=arc\csc x$

You might be interested in

What is the answer to (−t/3)^2?

Sloan [31]

Answer:

Simplify the expression.

t^/9

Step-by-step explanation:

7 0

3 years ago

Factorization of:

zubka84 [21]

Answer:

Step-by-step explanation:

2800: 2 * 2 * 2 * 2 * 5 * 5 * 7

75: 3 * 5 * 5

168: 2 * 2* 2 * 3 * 7

It's not really multiplication. It's more division.

Try 2800 as a sample. What you are trying to do is break this down into primes. The first prime is 2

2800/2 = 1400

1400 / 2 = 700

700 / 2 = 350

350 / 2 = 175. That's the end of what the 2s can do.

175 / 5 = 35

35/ 5 = 7 7 is a prime. You are done. Now run up the ladder.

2800: 2 * 2 * 2 * 2 * 5 * 5 * 7

75 is not an even number. It has no 2s. Go to 3

75 / 3 = 25.

25 / 5 = 5

That's the end

75: 3 * 5 * 5

Your calculator can be of great help. The rule is keep factoring until you get a decimal remainder. Move on to the next prime. Stop when the last division gives you a prime.

3 0

3 years ago

1. Express <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%282x%2B3%29%20%7D" id="TexFormula1" title="\frac{1}{x(2x+3) }" a

katovenus [111]

1. Let a and b be coefficients such that

$\dfrac1{x(2x+3)} = \dfrac ax + \dfrac b{2x+3}$

Combining the fractions on the right gives

$\dfrac1{x(2x+3)} = \dfrac{a(2x+3) + bx}{x(2x+3)}$

$\implies 1 = (2a+b)x + 3a$

$\implies \begin{cases}3a=1 \\ 2a+b=0\end{cases} \implies a=\dfrac13, b = -\dfrac23$

so that

$\dfrac1{x(2x+3)} = \boxed{\dfrac13 \left(\dfrac1x - \dfrac2{2x+3}\right)}$

2. a. The given ODE is separable as

$x(2x+3) \dfrac{dy}dx} = y \implies \dfrac{dy}y = \dfrac{dx}{x(2x+3)}$

Using the result of part (1), integrating both sides gives

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + C$

Given that y = 1 when x = 1, we find

$\ln|1| = \dfrac13 \left(\ln|1| - \ln|5|\right) + C \implies C = \dfrac13\ln(5)$

so the particular solution to the ODE is

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + \dfrac13\ln(5)$

We can solve this explicitly for y :

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3| + \ln(5)\right)$

$\ln|y| = \dfrac13 \ln\left|\dfrac{5x}{2x+3}\right|$

$\ln|y| = \ln\left|\sqrt[3]{\dfrac{5x}{2x+3}}\right|$

$\boxed{y = \sqrt[3]{\dfrac{5x}{2x+3}}}$

2. b. When x = 9, we get

$y = \sqrt[3]{\dfrac{45}{21}} = \sqrt[3]{\dfrac{15}7} \approx \boxed{1.29}$

8 0

2 years ago

Bruce evaluates the expression on a math quiz, 8.8 ÷ 2.7 and gets an answer of 4.14.

ella [17]

The correct answer is choice d.....

4 0

3 years ago

Read 2 more answers

What is the slope of the line shown in the graph? A)-5 B)-1/5 C)5 D)1/5

zhuklara [117]

Answer:

Step-by-step explanation:

To find the slope, you use rise/run. In this case... the rise is 5 up and the run is 1 across. Therefore it is 5/1 which is the same as 5. Hope this helped!

3 0

2 years ago

Read 2 more answers