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3 years ago

What is the constant in the expression 6a + 2b + 5?

Mathematics

1 answer:

goldenfox [79]3 years ago

8 0

Answer:

5 is the constant since it doesn't have any variable with it

Step-by-step explanation:

Hope this helps!

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Find (ƒ – g)(x) where ƒ(x) = 2x2 + 5x – 8, g(x) = –x2 + 6x.

STatiana [176]

Answer:

Step-by-step explanation:

ƒ(x) = 2x2 + 5x – 8

g(x) = –x2 + 6x

(ƒ – g)(x)=2x2+5x-8-(-x2+6x)

=2x2+5x-8+x2-6x

=3x2-x-8

6 0

3 years ago

How many solutions does the system of equations 5x−4y=8 and 5x−4y=2 have?

Rama09 [41]

Answer:

1 solution. y= 5/4x - 1/2

3 0

3 years ago

In triangle ABC , side AB is 6 and side AC is 4: Which statement is needed to prove that segment DE is parallel to segment BC an

Andreyy89

Answer:

Segment AD is 3, and segment AE is 2.

Step-by-step explanation:

In a triangle, the line joining the mid points of two sides is parallel and half of the third sides of the triangle.

Here, ABC is a triangle,

In which,

AB = 6,

AC = 4,

D∈ AB and E∈AC

Let DE ║BC,

And, $DE=\frac{1}{2}BC$

In triangles ADE and ABC,

$\angle ADE\cong \angle ABC$ ( Alternative interior angle theorem )

$\angle AED\cong \angle ACB$

By AA similarity postulate,

$\triangle ADE\sim \triangle ABC$

∵ Corresponding sides of similar triangle are in same proportion,

$\implies \frac{AD}{AB}=\frac{AE}{AC}=\frac{DE}{BC}$

$\frac{AD}{AB}=\frac{AE}{AC}=\frac{BC}{2BC}$

$\frac{AD}{AB}=\frac{AE}{AC}=\frac{1}{2}$

$\implies AD = \frac{AB}{2}\text{ and }AE =\frac{AC}{2}$

$\implies AD = \frac{6}{2}=3\text{ and }AE =\frac{4}{2}=2$

Hence, the correct option would be,

Segment AD is 3, and segment AE is 2.

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3 years ago

Help<br>ques starts frm a rectangular garden

yuradex [85]

Answer:

this is the full solution of your question

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3 years ago

Help mayyy pleaseee and tyy

Kay [80]

Answer:

2x=-7y not sure tho just guessping probably wrong sorry

Step-by-step explanation:

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3 years ago

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