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andreev551 [17]
3 years ago
9

What is the constant in the expression 6a + 2b + 5?

Mathematics
1 answer:
goldenfox [79]3 years ago
8 0

Answer:

5 is the constant since it doesn't have any variable with it

Step-by-step explanation:

Hope this helps!

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Simplify 15(2/5+1 1/3)+3
loris [4]
So for order of operations you start inside the parentheses and in order to add the insides you will need a common denominator which would be 15 on the bottom. So for 2/5 it would be 6/15 and for 11/3 would be 55/15 and then added together it would be 61/15. so then you would multiply and get 15(61/15). the 15 in the numerator will cancel with the denominator leaving only 61 and then the final step would be adding the 3 to 61 and the final answer will be 64
8 0
3 years ago
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What's 16.6666667 to the nearest tenth 
sasho [114]
16.7 is the answer rounded to the nearest tenth.
3 0
3 years ago
The owner of a new pet store wishes to display tropical fish in display tanks. The above table shows the species that cannot liv
Pepsi [2]

Answer:

The minimum number of different tanks needed to safely house all the fish is:

  • <u>3 tanks</u>.

Step-by-step explanation:

To identify the minimum number of different tanks, we're gonna concentrate in a fish species, in this case can be the A: as you see in the table, the A species can live with all the fish excepting the F and G, by their side, the F and G can't live together , by this reason, this three species must live in a different tank, in the next form:

  • Tank 1: <em>A</em>
  • Tank 2: <em>F</em>
  • Tank 3: <em>G</em>

Now the B species, it can live with A, F and G, but for this example we can put in the tank 1 (the tank of the A species). The C especies can live with A, F and G, but how we have A and B together, we're gonna put the C especies in the tank 3 (the tank of the G especies). The D species can live with A and G, we're gonna put in the tank 1 because can live with B species too. The E species can live with A and F, we're gonna put in the tank 2 (the tank of the F species) because the E species can't live with D that is in the in the tank 1. Al last, the H species just can live with A, E, F, and H species, by this reason, the only tank that can be put is the tank 2. In this form, the order is the next:

  • Tank 1: <em>A, B, D</em>.
  • Tank 2: <em>F, E, H</em>.
  • Tank 3: <em>G, C</em>.

And t<u>he owner of the pet store must buy three different tanks to display these tropical fish</u>.

5 0
3 years ago
A wildlife shelter is home to birds, mammals, and reptiles. If cat chow is sold in 30 lb bags, what is the least number of bags
kotykmax [81]

Answer:

26 bags

Step-by-step explanation:

A bag of cat chows = 30 lbs

Amount of cat chows needed in a week = 15 lbs = ½ bag of cat chow

There are at least 52 weeks in a year.

The least number of cat chows bags needed at the shelter in 1 year = 52 weeks × ½ bag of chow

= 52 × ½

= 52/2

= 26 bags of cat chow

At least, 26 bags would be needed in 1 year (52 weeks) at this wild life shelter if 15 lbs is consumed weekly.

4 0
3 years ago
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Ndicate the answer choice that best completes the statement or answers the question.
kirill115 [55]

Answer:

I think the answer is "adjacent, supplementary".

4 0
2 years ago
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