Answer:
(2a +b)·(13a^2 -5ab +b^2)
Step-by-step explanation:
The factorization of the difference of cubes is a standard form:
(p -q)^3 = (p -q)(p^2 +pq +q^2)
Here, you have ...
so the factorization is ...
(3a -(a -b))·((3a)^2 +(3a)(a -b) +(a -b)^2) . . . . substitute for p and q
= (2a +b)·(9a^2 +3a^2 -3ab +a^2 -2ab +b^2) . . . . simplify a bit
= (2a +b)·(13a^2 -5ab +b^2) . . . . . . collect terms
Perhaps you mean "slope-intercept" form. Solve for y and reduce the fractions.
.. -8x -6 = 2y . . . . . . . . add 2y-6
.. y = -4x -3 . . . . . . . . . divide by 2
Your line in slope-intercept form is
.. y = -4x -3
the marked angles are complementary → B
All 3 triangles are right with one angle = 90°
the sum of the angles in a triangle = 180°
thus the remaining 2 marked angles sum to 90°, thus are complementary
Answer: y=-8
Step-by-step explanation:
If the slope is zero that means that the line does not go up (or have any rise) and therefore must be a horizontal line. Since it passes through the point (3,-8), the equation has to be y=-8.
Answer:
the answer is -Xax.
Step-by-step explanation:
