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kogti [31]
3 years ago
15

Please help with answers to the last 2 rows

Mathematics
1 answer:
ELEN [110]3 years ago
4 0
Just do what you would do if you multiply double digit numbers expect with an extra digit. then count how many numbers are behind the decimal and when your down put the decimal point as much to the left from how many numbers are originally behind the decimal.
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Please Help me!!! <br><br><br> I know the answer but I don’t understand how to get that answer
worty [1.4K]
-7 ÷ 2 1/2
Okay, so first, put the -7 over one and make 2 1/2 an improper fraction. so now:
-7/1 ÷ 5/2
Then, take the reciprocal of 5/2 and multiply it by -7/1
-7/1 × 5/2
Which would be -35/2
5 0
3 years ago
Under his cell phone plan, Elijah pays a flat cost of $64.50 per month and $5 per gigabyte. He wants to keep his bill at $87.50
photoshop1234 [79]
Gotta go stingy by adding 64.5 us 87.5
6 0
2 years ago
Can someone please help me. It's for the elimination method.
mojhsa [17]
Since there is 101 Tickets, 
Let S + A = 101
1.50S + 2.50A = $186.50



Adults + Students = 101

$186. 50 = $2.50 Adults + $1.50 Students

Answer is 35 Adults, and 66 Students.




Hope that helps!!!
6 0
2 years ago
The rate of growth of profit​ (in millions) from an invention is approximated by Upper P prime (x )equals x e Superscript negati
Alecsey [184]

Answer:

The function is  P(x) =  \frac{1}{2} e^{-x^2} +0.016

Step-by-step explanation:

From the question we are told that

    The rate of growth  is  P'(x) =  xe^{x} - x^2

     The total profit is P(2)  =$25,000

      The time taken to make the profit is x =  2 \ years

         

From the question

     P'(x) =  xe^{-x^2}  is the rate of growth

  Now here x represent the time taken

Now the total profit is mathematically represented as

       P(x) =  \int\limits {P'(x)} \,  =   \int\limits {xe^{-x^2}} \,

So using substitution method

   We have that

                      u =  - x^2

                      du =  2xdx

  So  

        p(x) =  \int\limits {\frac{1}{2} e^{-u}} \, du

       p(x) =  {\frac{1}{2} [ e^{-u}} +c ]

       p(x) =  {\frac{1}{2}  e^{-x^2}} + \frac{1}{2} c      recall  u =  - x^2   and  let  \frac{1}{2} c =  Z

       

At  x =  2 years  

     P(x)  =$25,000

So

       Since the profit rate is in million

    P(x)  =$25,000 = \frac{25000}{1000000} =$0.025 millon dollars

So  

       0.025 =  {\frac{1}{2}  e^{-2^2}} + Z  

=>    Z = 0.025 - {\frac{1}{2}  e^{-2^2}}  

       Z = 0.016  

So the profit function becomes

         P(x) =  \frac{1}{2} e^{-x^2} +0.016

     

       

5 0
3 years ago
4x/x-5 - 3/x-6 simplify
blagie [28]

Answer

-3

Step-by-step explanation:

x=4

4-5=-1

x=3

3-6=-2

-1+-2=-3

7 0
2 years ago
Read 2 more answers
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