Answer:
Step-by-step explanation:
Answer:
Number of $5 bills = 32
Number of $10 bills = 14
Number of $20 bills = 8
Step-by-step explanation:
Let x number of $5, y number of $10 and z number of $20
The number of $5 bills exceeds twice the number of $10 bills by 4.
Therefore, x = 2y + 4
The number of $20 bills is 6 fewer than the number of $10 bills.
Therefore, z = y - 6
A wallet contains $460 in $5, $10, and $20 bills.
Therefore,
5x + 10y + 20z = 460
Substitute x and y into equation
5(2y+4) + 10y + 20(y-6) = 460
10y + 20 + 10y + 20y - 120 = 460
40y - 100 = 460
40y = 460 + 100
40y = 560
y = 14
- Put the value of y into x = 2y + 4 and solve for x
x = 2(14) + 4
x = 32
- Put the value of y into z = y - 6 and solve for z
z = 14 - 6
z = 8
Hence, the each type of bills,
Number of $5 bills = 32
Number of $10 bills = 14
Number of $20 bills = 8
Answer:
x=7
Step-by-step explanation:
2(x+5)=24
2(x)+2(5) =24
2x +10=24
- 10 -10
2x=14
2x/2x 14/2x
x=7
Hope this helps :)
Answer:
The correct answer is:
(1) d
(2) b
(3) a
(4) c
(5) e
Step-by-step explanation:
The given problem is incomplete. Find the attachment of the full question.
According to the question,
(1)
By putting x = -2, we get
(2)
By putting x = 0, we get
(3)
By putting x = 3, we get
(4)
By putting x = 9, we get
(5)
By putting x = 11, we get
