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Ray Of Light [21]
3 years ago
11

The sum of the measures of Angle A and Angle B is 180°.

Mathematics
1 answer:
In-s [12.5K]3 years ago
4 0

Answer:

x=9

Step-by-step explanation:

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Find all complex solutions of 5x^2+5x+3=0.
oksian1 [2.3K]

Answer:

see explanation

Step-by-step explanation:

5x² + 5x + 3 = 0 ← in standard form

with a = 5 , b = 5 , c = 3

Solve using the quadratic formula

x = \frac{-b+/-\sqrt{b^2-4ac} }{2a}

  = \frac{-5+/-\sqrt{5^2-(4(5)(3)} }{2(5)}

  = \frac{-5+/-\sqrt{25-60} }{10}

  = \frac{-5+/-\sqrt{-35} }{10}

  = \frac{-5+/-\sqrt{-1(35)} }{10}

 = \frac{-5+/-i\sqrt{35} }{10}

Then

x = \frac{-5}{10} ± \frac{1}{10} i\sqrt{35} , that is

x = - \frac{1}{2} - \sqrt{x} \frac{1}{10} i\sqrt{35} , - \frac{1}{2} + \frac{1}{10} i\sqrt{35}

5 0
3 years ago
Solve for r. k=3r-7s
const2013 [10]
R=7s/3+k/3

Hope this helps!
5 0
3 years ago
NO EXPLANATION NEEDED
Degger [83]
10/2 so 5 for 53, 10/4 so 5/2 or 2.5 for 54, and 10/3 or 3.333. For simplicity i divided everything by 10 to remove an extra zero but the answers would still be the same after you reduced
3 0
3 years ago
Number 15 please help
OverLord2011 [107]
I would believe its 10
4 0
3 years ago
How many students were enrolled by the end of the fourteenth century at the university of salamanca?
zmey [24]
There were about 500 to 600 students that attended the University of salamanca by the end of the 14th century
5 0
3 years ago
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