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guajiro [1.7K]
3 years ago
13

28 divided by 52 by using long division

Mathematics
1 answer:
OLga [1]3 years ago
3 0

yea this is a tough one it wouldn't even have a full number t would be decimals

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Find the pay earned: 33 hours at $5.15 per hour
Inessa [10]
$169.95 

33*5.15=169.95
5 0
3 years ago
Read 2 more answers
Write and solve a system of linear equations: The larger of two numbers is 18 more than 5 times the smaller. If 3 times the larg
marshall27 [118]

Answer:

8 and -2

Step-by-step explanation:

Let the numbers be l and s.

We have equations:

l = 5s + 18

3l + 4s = 16

Solve for s by substituting l into the second equation:

3(5s + 18) + 4s = 16

15s + 54 + 4s = 16

19s = 16 - 54

19s = -38

s = -38/19

s = -2

Find the value of l:

l = 5(-2) + 18

l = -10 + 18

l = 8

3 0
2 years ago
Evaluate 5x – 2y + (7x – y) for x = 7 and y = –2. 90 –18 –45 63
seropon [69]

The value of the expression 5x – 2y + (7x – y)  when x = 7 and y = -2 is 90

<h3>How to evaluate the expression?</h3>

The expression is given as:

5x – 2y + (7x – y)

Substitute x = 7 and y = –2 in the above expression

5 * 7 - 2 * -2 + (7 * 7 + 2)

Evaluate the expression

90

Hence, the value of the expression 5x – 2y + (7x – y)  when x = 7 and y = -2 is 90

Read more about expressions at:

brainly.com/question/723406

#SPJ1

8 0
2 years ago
The half-life of caffeine in a healthy adult is 4.8 hours. Jeremiah drinks 18 ounces of caffeinated
statuscvo [17]

We want to see how long will take a healthy adult to reduce the caffeine in his body to a 60%. We will find that the answer is 3.55 hours.

We know that the half-life of caffeine is 4.8 hours, this means that for a given initial quantity of coffee A, after 4.8 hours that quantity reduces to A/2.

So we can define the proportion of coffee that Jeremiah has in his body as:

P(t) = 1*e^{k*t}

Such that:

P(4.8 h) = 0.5 = 1*e^{k*4.8}

Then, if we apply the natural logarithm we get:

Ln(0.5) = Ln(e^{k*4.8})

Ln(0.5) = k*4.8

Ln(0.5)/4.8 = k = -0.144

Then the equation is:

P(t) = 1*e^{-0.144*t}

Now we want to find the time such that the caffeine in his body is the 60% of what he drank that morning, then we must solve:

P(t) = 0.6 =  1*e^{-0.144*t}

Again, we use the natural logarithm:

Ln(0.6) = Ln(e^{-0.144*t})

Ln(0.6) = -0.144*t

Ln(0.6)/-0.144 = t = 3.55

So after 3.55 hours only the 60% of the coffee that he drank that morning will still be in his body.

If you want to learn more, you can read:

brainly.com/question/19599469

7 0
2 years ago
Factorise this please​
ahrayia [7]

Answer:

x^4 - 3y^4 -2

your welcome

5 0
2 years ago
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