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Oksi-84 [34.3K]
3 years ago
14

Select the term that best describes the statement A triangle is acute provided all the angles have a measure of less than 90 deg

rees.
A.Conjunction
B.disjunction
C. negation
D.conditional
Mathematics
2 answers:
Aloiza [94]3 years ago
4 0
I think the correct answer is conjunction...
k0ka [10]3 years ago
3 0

Answer:

Conditional statement is the answer.                  

Step-by-step explanation:               

The answer is a conditional statement.                    

Conditional statements has 2 clause p and q. These are based on the if-then clause where p is a hypothesis and q is a conclusion.

Here, it is given that - A triangle is acute provided all the angles have a measure of less than 90 degrees.

A triangle to be an acute triangle, the condition is that all its angles must measure less than 90 degrees. It is a CONDITION that a triangle must satisfy, in order to be called an acute triangle.

Therefore, conditional is the answer.

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Answer:

three and five hundreths

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xxTIMURxx [149]

Answer:

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

p_v =2*P(t_{(1699)}>1.971)=0.049  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

Step-by-step explanation:

Data given and notation  

\bar X=669 represent the sample mean

s=732 represent the sample standard deviation

n=1700 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0. represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different from 634, the system of hypothesis would be:  

Null hypothesis:\mu = 634  

Alternative hypothesis:\mu \neq 634  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=1700-1=1699  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(1699)}>1.971)=0.049  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

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Answer:

I'm going to write both of these because maybe you have a fill in the blank question. I don't know.

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Step-by-step explanation:

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Let's plug this in.

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Step-by-step explanation:

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