Question

What are the coordinates of vertex J of the pre-image? (0, -4) (0, -1) (0, 0) (0, 4)

Answer 1

Answer:

(0,-4)

Step-by-step explanation:

The complete question is

Quadrilateral JKLM was dilated according to the rule    

DO,1/2 (x,y)( 1/2x1/2y) to create the image quadrilateral J'K'L'M', which is shown on the graph.

What are the coordinates of vertex J of the pre-image?

The picture in the attached figure

we know that

The rule of the dilation is

(x,y) -----> (1/2x,1/2y)

The coordinates of vertex J' are (0,-2) ----> see the graph

therefore

The x-coordinate of J (pre-image) multiplied by 1/2 must be equal to the x-coordinate of J' (image)

$\frac{1}{2}x=0$ -----> $x=0$

The y-coordinate of J (pre-image) multiplied by 1/2 must be equal to the y-coordinate of J' (image)

$\frac{1}{2}y=-2$ -----> $y=-4$

therefore

The coordinates of J are (0,-4)

Answer 2

Answer:

D

Step-by-step explanation:

edge