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bixtya [17]
2 years ago
15

CLASS PROJECT An economics class formed a company to sell school supplies. They would like to sell at least 20 notebooks and 50

pens per week, with a goal of earning at least $60 per week. a. Define the variables, and write a system of inequalities to represent this situation. b. Graph the system. c. Name one possible solution.​
Mathematics
1 answer:
lesya692 [45]2 years ago
8 0

Answer:

60≥20x+50y

Step-by-step explanation:

Let x = notebooks and y = pens (all per week)

One solution would be x ≥ 1 and y ≥ 1 as at least one per each item per week

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Solve using the quadratic formula 3x^2+11x+5=0
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Answer:

3x^2 + 11x + 5 = 0 : x = \frac{-11 + \sqrt{61} }{6} , x = \frac{-11 - \sqrt{61} }{6}

Decimal:

(x = -0.53162..., x = -3.13504...)

Step-by-step explanation:

3x^2+11x+5=0

Solve with the quadratic formula:

For a quadratic equation of the form ax^2+bx+c=0 the solutions are:

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

For a=3,\:b=11,\:c=5:\quad x_{1,\:2}=\frac{-11\pm \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}

x=\frac{-11 + \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 + \sqrt{61} }{6}

x=\frac{-11 - \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 - \sqrt{61} }{6}

The solutions to the quadratic equation are:

x=\frac{-11+\sqrt{61}}{6},\:x=\frac{-11-\sqrt{61}}{6}

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day! =)

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