All categories

3 years ago

One number is 5 more than another.

Mathematics

2 answers:

Ganezh [65]3 years ago

7 0

Answer: 29 and 24

Step-by-step explanation:

Since one number is 5 more than another

53-5 = 48

Then we divide that by two to get the value of one of the two numbers

48/2= 24

In order to get the number which is 5 more than the other, we add 5

24+5= 29

So the two numbers would be 29 and 24.

Check:

29+24= 53

makkiz [27]3 years ago

7 0

Answer: 24 and 29

<u>Step-by-step explanation:</u>

Let x represent one of the numbers, then the other number is x + 5.

"sum" means to add them, so lets add x and x + 5 and set it equal to 53

x + x + 5 = 53

2x + 5 = 53 <em>simplified</em>

2x = 48 <em>subtracted 5 from both sides</em>

x = 24 <em>divided 2 from both sides</em>

So one of the numbers is 24. The other number is x + 5

= 24 + 5

= 29

You might be interested in

The record high temperature in January was 18 degrees. The record low temperature was –7 degrees. What is the amount of change b

vodka [1.7K]

Answer: $25^{\circ}$

Step-by-step explanation:

Given

The highest temperature recorded is $18^{\circ}$

The lowest temperature recorded is $-7^{\circ}$

The amount of change between the high and the low temperatures is

$\Rightarrow 18-(-7)=18+7\\\Rightarrow 25^{\circ}$

6 0

3 years ago

Select the two values of x that are roots of this equation

Jet001 [13]

<h2>Hello!</h2>

The answers are:

B. $\frac{-3-\sqrt{29}}{2}$

C. $\frac{-3+\sqrt{29}}{2}$

We can use the quadratic equation to find the two values of x that are roots of the given equation. We must remember that most of the quadratic equations have two roots, however, we could find quadratic equations with just one root or even with no roots, at least in the real numbers.

Quadratic equation:

$\frac{-b+-\sqrt{b^{2}-4ac} }{2a}$

So,

From the given equation we have:

$a=1\\b=3\\c=-5$

Substituting it into the quadratic equation to find the roots, we have:

$\frac{-b+-\sqrt{b^{2}-4ac} }{2a}=\frac{-3+-\sqrt{3^{2}-4*1*-5} }{2*1}\\\\\frac{-3+-\sqrt{3^{2}-4*1*-5} }{2*1}=\frac{-3+-\sqrt{9+20} }{2}\\\\\frac{-3+-\sqrt{29}}{2}$

So,

$x_{1}=\frac{-3-\sqrt{29}}{2}\\\\x_{2}=\frac{-3+\sqrt{29}}{2}$

Hence, the correct options are B and C.

7 0

3 years ago

Graph -27x+18y=54 Help please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Marta_Voda [28]

Answer:

slope : 3/2 Y-intercept : 3 ------------> (0,3) (2,6) are the points

Step-by-step explanation:

0 | 3

2 | 6

4 0

3 years ago

Question 7

Elina [12.6K]

D is right because there is not tire

5 0

3 years ago

How to factorise 5a squared - 4ab

Marizza181 [45]

You can take the a out of both values. There are no other factorable parts of this expression. Your factored version would look something like this- a(5a-4b)
Hope that helped you out a bit nuzhat! ☺️

8 0

3 years ago

Read 2 more answers