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3 years ago

Find the equation of the parabola with a vertex of (5, -2) and a focus of (5, -3)

1 answer:

6 0

Use the form $\left(x-h\right)^2=\frac{1}{4p}\left(y-k \right)$
Then we have the vertex is $(h,k)$ and the distance from the vertex to the focus is p. Therefore we have $\left(x-5\right)^2=-\frac{1}{4}\left(y+2\right)$ . It is negative because the parabola is pointing downwards.

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Which expression is a difference of squares with a factor of 2x + 5? 4x2 + 10 4x2 – 10 4x2 + 25 4x2 – 25

aleksley [76]

I hope this helps you

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3 years ago

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A baker purchased 10 lb of wheat flour and 13 lb of rye flour for a total cost of $17.40. A second purchase, at the same prices,

fiasKO [112]

wheat = $0.96 lb rye = $1.89 lb

12w + 15r = 3987 15w + 10r = 3330 r = (3330 - 15w)/10 12w + 15r = 3987 12w + 15((3330 - 15w)/10) = 3987 12w + (15/10)(3330 - 15w) = 3987 12w + 4995 - 22.5w = 3987 10.5w = 1008 w = 96 cents r = 189 cents.

Hope this helps mate

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3 years ago

From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ

bulgar [2K]

Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given by $P(x)=C(n,x)p^x(1-p)^{n-x}$ where $C(n,x)=\frac{n!}{x!(n-x)!}$
Here we're given
p=0.10 [ success = defective ]
n=3

(a) x=0
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,0)0.1^0(1-0.1)^{3-0}$
$=1(1)(0.729)$
$=0.729$

(b) x=2
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,2)0.1^2(1-0.1)^{3-2}$
$=3(0.01)(0.9)$
$=0.027$

(c) x ≥ 2
$P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}$
$=P(2)+P(3)$
$=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}$
$=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}$
$=3(0.01)(0.9)+1(0.001)1$
$=0.027+0.001$
$=0.028$

8 0

3 years ago

Jason wanted to buy postcards for his cousin. The price was 2 cards for $1. He had some change in his pocket. What combination o

Zina [86]

Answer:

2 dimes, 1 nickel and 3 quarters.

Step-by-step explanation:

The price of 2 postcards is $1. Any combination of coins that adds to $1 will work here. Remember, a penny is worth 0.01, a nickel is worth 0.05, a dime is worth 0.10, and a quarter is worth 0.25.

Adding 2 dimes, 1 nickel, and 3 quarters would be 2(0.10)+1(0.05)+3(0.25)=1.

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3 years ago

4. Joe likes sports. He has 4 soccer medals, 1 tennis medal, 3 swimming medals and 5

Lady_Fox [76]

Answer:

4:3

Step-by-step explanation:

He has 4 Soccer Medals, 3 Swimming Medals

So it would be 4:3

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3 years ago