Answer:
76%
Step-by-step explanation:
So basically 528 represents a full circle and the amount in the circle is 2:5 to that in the stalls.
So you divide 528 by 2 and then multiply it by 5 to get a full stall of 1320
you then add 1320 and 528 to get a full theater of 1848
to get 2/3 of seats in the stall you divide 1320 by 3 and then multiply it by 2 to get 880.
For 2/3 of the stall and a full circle you add 880 and 528 to get 1408.
You divide the amount of people in the theater on Friday by the total amount of people which the theater can hold so 1408 divided by 1848 and you get the percentage of 76%
Answer:
The quantity of water in the tank after 15 days is 1610.0 gallons OR 1.61 × 10³ gallons.
Step-by-step explanation:
The amount of water in the tank after 15 days is given by the series
910+(−710)+810+(−610)+⋯+310+(−110)+210
From the series, we can observe that, if water is added for a particular day then water will be drained the following day.
Also, for a day when water is to be added, the quantity to be added will be 100 gallon lesser than the quantity that was last added. Likewise, for a day when water is to be drained, the quantity to be drained will be 100 gallons lesser than the quantity that was last drained.
Hence, we can complete the series thus:
910+(−710)+810+(−610)+710(-510)+610(-410)+510(-310)+410(-210)+310+(−110)+210
To evaluate this, we get
910-710+810-610+710-510+610-410+510-310+410-210+310-110+210
= 1610.0 gallons
Hence, the quantity of water in the tank after 15 days is 1610 gallons OR 1.61 × 10³ gallons.
Answer: 0.9862
Step-by-step explanation:
Given : The probability that the chips belongs to Japan: P(J)= 0.36
The probability that the chips belongs to United States : P(U)= 1-0.36=0.64
The proportion of Japanese chips are defective : P(D|J)=0.017
The proportion of American chips are defective : P(D|U)=0.012
Using law of total probability , we have
Thus , the probability that chip is defective = 0.0138
Then , the probability that a chip is defect-free=
