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bogdanovich [222]
3 years ago
12

A product with an annual demand of 1000 units has Co = $25.50 and Ch = $8. The demand exhibits some variability such that the le

ad-time demand follows a normal probability distribution with μ=25 and σ=5. a.What is the recommended order quantity? b. What are the recorder point and safety stock if the firm desires at most a 2% probability of stockout on any given order cycle? c. If a manager sets the reorder point at 30, what is the probability of a stockout on any given order cycle? How many times would you expect a stockout during the year if the reorder point were used?

Mathematics
1 answer:
frosja888 [35]3 years ago
7 0

Answer:

a) Recommended order quantity = 79.84 = 80

b) recorder point = 35

Safety stock = 10

Safety stock cost = $0/year

ci) P(stock out/cycle) = 0.1587

cii) Number of stock outs/ year = 2

Step-by-step explanation:

The pictures attached show a clear explanation of all the processes.

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Simplify (3х2 – 2) + (2х2 – бх + 3).
kolbaska11 [484]

Answer:

5x^2 -6x +1

Step-by-step explanation:

(3х^2 – 2) + (2х^2 – бх + 3).

Combine like terms

(3х^2  + 2х^2 – бх + 3-2)

5x^2 -6x +1

4 0
3 years ago
Please help. I’ll mark you as brainliest if correct!
chubhunter [2.5K]

Answer:

\boxed{\sf \ \ \ f^{-1}(x)=1+\sqrt{x} \ \ \ }

Step-by-step explanation:

the minimum of f is for x = 1 and f(1)=0

f is decreasing for x<=1 and increasing for x>=1

so the domain is [1;+\infty[

f^{-1}(f(x))=x =f^{-1}((x-1)^2)\\\\f(f^{-1}(x))=x=(f^{-1}(x)-1)^2

x>=1 so x is positive and we can take the square root

so f^{-1}(x)=1+\sqrt{x}

8 0
3 years ago
Find the distance between the points (2, 4) and (8,-8) on a coordinate plane, to the nearest whole number.
Alisiya [41]

Answer:

2,5

Step-by-step explanation:

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8 0
3 years ago
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3 0
3 years ago
Read 2 more answers
When Alice spends the day with the babysitter, there is a 0.6 probability that she turns on the TV and watches a show. Her littl
lara [203]

Answer:

A. P("Both Alice and Betty watch TV") = 12/25

B. P("Betty watches TV") = 12/25

C. P("Only Alice watches TV") = 3/25

Step-by-step explanation:

A. Because what we are told, Betty need that Alice turn on the TV, so, we first need the probability that she watches TV:

P(Alice)=3/5 (0.6)

And we know that:

P(Betty)=4/5 (0.8)

If we want the probability of both things happening at the same time (If you use a tree diagram, those events will be in the same branch), we proceed multiply them:

P("Both Alice and Betty watch TV") = 3/5 * 4/5 = 12/25

And this is the answer

B. Considering that Betty needs Alice to turn on the TV, the probability of Betty watching TV is the same as if she is with Alice.

P("Betty watches TV") = P("Both Alice and Betty watch TV") = 12/25

C. We use the same process as part A, but with a little difference. We now multiply for the probability that Betty does not watch TV (Because they still be in the same branch).

P("Betty does not watch TV") = 1 - P("Betty")

P("Betty does not watch TV") = 1 - 4/5

P("Betty does not watch TV") = 1/5

And the answer for part C is:

P("Alice watches TV without Betty") = 3/5 * 1/5 = 3/25

5 0
3 years ago
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