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melamori03 [73]
3 years ago
7

Tricia has $37.25 in her account. Which shows the amount she will have left after she writes a check for $23.99?

Mathematics
1 answer:
aliya0001 [1]3 years ago
4 0
C :) brainiest? This is correct because I did the math lol
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Carla's retirement party will cost $15 if she invites 3 guests. If there are 4 guests, how much will Carla's retirement party co
LekaFEV [45]

Answer:

$20

Step-by-step explanation:

15/3=5 which means that for every guest attending Carla's retirement party it must cost her $5 each.

Therefore if 4 guests come to the party it must mean 4(5) which is 20.

Hence $20

7 0
3 years ago
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Y=x²-6x+8 what is y when x is 0?
jarptica [38.1K]

Answer:

The value of y is 8.

Step-by-step explanation:

In order to find the value of y, you have to put in x = 0 into the equation :

y =  {x}^{2}  - 6x + 8

Let x = 0,

y =  {0}^{2}  - 6(0) + 8

y = 8

6 0
4 years ago
5(2x − 12) + 21 = 2x + 41<br><br> I know the answer is 10 but can someone explain how to get that?
dsp73
5(2x-12)+21=2x+41\\\\5\cdot2x-5\cdot12+21=2x+41\\\\10x-60+21=2x+41\\\\10x-39=2x+41\qquad|+39\\\\10x-39+39=2x+41+39\\\\10x=2x+80\qquad|-2x\\\\10x-2x=2x+80-2x\\\\8x=80\qquad|:8\\\\\boxed{x=10}
6 0
3 years ago
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Find the average rate of change.
alina1380 [7]

The average rate of change = 1.59 ≈ 2

The average rate of change can be calculated by

1) The first one = \frac{3 + 0}{2} = 1.5

2 ) the second can also be solved by ; 8 + 2/ 2 = 5

3 ) the third one will be 20 + 6 / 2 = 13

4) 8.5

5) 12.5

To calculate the average rate of change

we will first add all the distance

Adding all the distance we will get the sum = 3 + 8 + 20 + 10 + 10 = 51

The total time = 2 + 6 + 9 +15 = 32

Thus the average rate of change = 51 / 32 = 1.59

To know more about average rate of change you may visit the link which is mentioned below;

brainly.com/question/28744270

#SPJ13

5 0
1 year ago
Is this graph proportional or non-proportional?
grigory [225]

Answer:

Yes

Step-by-step explanation:

The slope intercept form is y=1.38x

8 0
3 years ago
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