Answer:
Patrick walk approximately <u>112 yards</u>.
Step-by-step explanation:
Given:
A rectangular field is 50 yards wide and 100 yards long.
Patrick walks diagonally across the field.
Now, to find the distance he walk.
Length of the field = 100 yards.
Width of the field = 50 yards.
Now, to get the diagonal distance we put formula:





Therefore, Patrick walk approximately 112 yards.
Answer:
1.) m= — 25/21 2.) m = 0 3.) m = —1/32
Step-by-step explanation:
Answer:
16
Step-by-step explanation:
Dealing with a fraction exponent on hand can be converted by using the fractional exponents rule where the fraction exponent is converted to something like this:
![64^\frac{2}{3} = \sqrt[3]{64^{2}}\\](https://tex.z-dn.net/?f=64%5E%5Cfrac%7B2%7D%7B3%7D%20%3D%20%5Csqrt%5B3%5D%7B64%5E%7B2%7D%7D%5C%5C)
As you can see, the denominator of the fractional exponent is now the index of the radical. Here is a guide to know what goes where.
![64^\frac{x}{y} = \sqrt[y]{64^{x}}](https://tex.z-dn.net/?f=64%5E%5Cfrac%7Bx%7D%7By%7D%20%3D%20%5Csqrt%5By%5D%7B64%5E%7Bx%7D%7D)
Both the original problem (64^2/3) and the converted formula can be put into a calculator.
<u>Simplify (if you want to)</u>
<u />
<u />
<u />
64 to the power of 2/3 is 16.
Answer:
c. 4.27
Step-by-step explanation:
We have been given the regression equation of for predicting number of speeding tickets (Y) from information about driver age (X) as
.
To find the predicted number of tickets for a twenty-year-old, we will substitute
in our given equation.



Therefore, the predicted number of tickets for a twenty-year-old would be 4.27 tickets.
<span><span><span><span><span><span>(<span>x+2</span>)</span><span>(<span>x<span>−2</span></span>)</span></span><span>(<span>x+1</span>)</span></span><span>(<span>x<span>−1</span></span>)</span></span></span><span>=0</span></span> true. x=−2,2,−1,1
hope this helps