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3 years ago

Help needed desperately

Mathematics

1 answer:

Aneli [31]3 years ago

8 0

Answer:

80° , 100°, 80°

Step-by-step explanation:

∠ 1 and ∠ 2 form a straight line and sum to 180° , then

2x + 40 + 2y + 40 = 180

2x + 2y + 80 = 180 ( subtract 80 from both sides )

2x + 2y = 100 → (1)

∠ 1 and ∠ 3 are vertical angles and are congruent , then

2x + 40 = x + 2y ( subtract x from both sides )

x + 40 = 2y ( subtract 40 from both sides )

x = 2y - 40 → (2)

Substitute x = 2y - 40 into (1)

2(2y - 40) + 2y = 100

4y - 80 + 2y = 100

6y - 80 = 100 ( add 80 to both sides )

6y = 180 ( divide both sides by 6 )

y = 30

Substitute y = 30 into (2)

x = 2(30) - 40 = 60 - 40 = 20

Thus x = 20 and y = 30

Then

∠ 1 = 2x + 40 = 2(20) + 40 = 40 + 40 = 80°

∠ 2 = 2y + 40 = 2(30) + 40 = 60 + 40 = 100°

∠3 = x + 2y = 20 + 2(30) = 20 + 60 = 80°

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There are 1 × 1014 good bacteria in the human body. There are 2.6 × 1018 good bacteria among the spectators in a soccer stadium.

grandymaker [24]

Answer:

There are $2.6\times 10^{4}$ spectators in the soccer stadium.

Step-by-step explanation:

From this statement, we can calculate the number of spectators in a soccer stadium by dividing the amount of bacteria among the spectators in a soccer stadium by the amount of bacteria in the human body. That is:

$x = \frac{2.6\times 10^{18}\,bacteria}{1\times 10^{14}\,bacteria}$

$x = \frac{2.6}{1}\times \frac{10^{18}}{10^{14}}$

$x = 2.6\times 10^{18-14}$

$x = 2.6\times 10^{4}$

There are $2.6\times 10^{4}$ spectators in the soccer stadium.

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3 years ago

Justin is a software salesman. his base salary is $1500 , and he makes an additional $40 for every copy of english is fun he sel

strojnjashka [21]

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3 years ago

Order −0.8, 2 3 , 1, −1 3 from least to greatest. Which order is correct?

True [87]

Answer:

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Step-by-step explanation:

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3 years ago

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Points P, Q and R are collinear such that PQ : QR=2:3 point P is located at (1,3) and point R is located at (11,15)

balandron [24]

Using line segments, it is found that:

The coordinates of Q are (5,7.8).

The midpoint of segment PQ is M(6,9).

----------------------------

Point P is located at (1,3).
Point R is located at (11,15).
Point Q is located at (x,y).
PQ:QR = 2:3, which means that:

$Q - P = \frac{2}{5}(R - P)$

This is used to find the x and y coordinates of Q.

----------------------------

The x-coordinate of P is 1.
The x-coordinate of R is 11.
The x-coordinate of Q is x.

Thus:

$Q - P = \frac{2}{5}(R - P)$

$x - 1 = \frac{2}{5}(11 - 1)$

$x - 1 = \frac{2}{5}10$

$x - 1 = 4$

$x = 5$

----------------------------

The y-coordinate of P is 3.
The y-coordinate of R is 15.
The y-coordinate of Q is y.

Thus:

$Q - P = \frac{2}{5}(R - P)$

$y - 3 = \frac{2}{5}(15 - 3)$

$y - 3 = \frac{24}{5}$

$y - 3 = 4.8$

$y = 7.8$

The coordinates of Q are (5,7.8).

----------------------------

The midpoint of segment PQ is the mean of the coordinates, thus:

$M = (\frac{1 + 11}{2}, \frac{3 + 15}{2}) = (\frac{12}{2}, \frac{18}{2}) = (6,9)$

The midpoint of segment PQ is M(6,9).

A similar problem is given at brainly.com/question/24148182

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3 years ago

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Valentin [98]

Answer:

16 5/12 years old

Step-by-step explanation:

Just add them all together. You need to find the LCD for them to do that.

Hope this helps!

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3 years ago

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