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yanalaym [24]
3 years ago
7

Non-preemptive Shortest Job First (SJF) scheduling policy is not optimal if:

Computers and Technology
1 answer:
ivann1987 [24]3 years ago
4 0

Answer:

The answer is A

Explanation:

Basically, Shortest job first (SJF) is a scheduling policy that selects jobs on queue for execution  within a short execution time.

From the definition of SJF above, it means that there are a lot of process on queue and the (SJF) job is to receive processes on queue to execute within a short execution time.

Therefore, if all the jobs or process arrives at the SJF at the same time, the SJF will forfeit one of its major purpose which is scheduling of jobs.

That will therefore not make Non-preemptive Shortest Job First (SJF) not function at its optimal point.

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The 60-watt light bulb has a 400 hour life expectency how much will it cost to operate during its time
expeople1 [14]

Answer:

$2.40

Explanation:

the unit electricity bill is kilo watt hour.

The 60-watt light bulb has a 400 hour life expectency means it will consume

60×400/1000 = 24 KWh units of electricity. Let us suppose each unit of electricity costs is 10 cents.

Then 24×10 = 240 cents  = $2.40

5 0
3 years ago
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Answer:

B. the current affairs page

Explanation:

it's a simple question

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Write a program that generates two 3x3 matrices, A and B, withrandom values in the range [1, 100] and calculates the expression½
Alex

Answer:

#include <bits/stdc++.h>

using namespace std;

int main() {

int A[3][3],B[3][3],res[3][3],i,j;

srand(time(0));//for seed.

for(i=0;i<3;i++)

{

   for(j=0;j<3;j++)

{

   int val=rand()%100+1;//generating random values in range 1 to 100.

   int val2=rand()%100+1;

   A[i][j]=val;

   B[i][j]=val2;

}

cout<<endl;

}

for(i=0;i<3;i++)

{

   for(j=0;j<3;j++)

   {

       res[i][j]=0.5*A[i][j]+3*B[i][j];//storing the result in matrix res.

   }

}

cout<<"Matrix A is"<<endl;

for(i=0;i<3;i++)

{

   for(j=0;j<3;j++)

   {

       cout<<A[i][j]<<" ";//printing matrix A..

   }

   cout<<endl;

}

cout<<"Matrix B is"<<endl;

for(i=0;i<3;i++)

{

   for(j=0;j<3;j++)

   {

       cout<<B[i][j]<<" ";//printing matrix B..

   }

   cout<<endl;

}

cout<<"The result is"<<endl;

for(i=0;i<3;i++)

{

   for(j=0;j<3;j++)

   {

       cout<<res[i][j]<<" ";//printing the result..

   }

   cout<<endl;

}

return 0;

}

Output:-

Matrix A is

13 95 83  

88 7 14  

24 22 100  

Matrix B is

11 13 95  

48 35 20  

68 100 18  

The result is

39.5 86.5 326.5  

188 108.5 67  

216 311 104  

Explanation:

I have created 2 matrices A and B and storing random numbers int the matrices A and B.Then after that storing the result in res matrix of type double to store decimal values also.Then printing the res matrix.

6 0
3 years ago
A previously saved labels report can be accessed from the
Tcecarenko [31]

C. is the answer to that question

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3 years ago
Which argument forces a writer to return to and change the input before resolving a “UnicodeError”?
garri49 [273]

Answer:

B

Explanation:

3 0
3 years ago
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