Answer:
- common = []
- num1 = 8
- num2 = 24
- for i in range(1, num1 + 1):
- if(num1 % i == 0 and num2 % i == 0):
- common.append(i)
- print(common)
Explanation:
The solution is written in Python 3.
Firstly create a common list to hold a list of the common factor between 8 and 24 (Line 1).
Create two variables num1, and num2 and set 8 and 24 as their values, respectively (Line 3 - 4).
Create a for loop to traverse through the number from 1 to 8 and use modulus operator to check if num1 and num2 are divisible by current i value. If so the remainder of both num1%i and num2%i will be zero and the if block will run to append the current i value to common list (Line 6-8).
After the loop, print the common list and we shall get [1, 2, 4, 8]
The number and letter are switched. This question needs more context to get a accurate answer.
Answer:
it would be B hope this helps
Explanation:
Answer:
1.152 GB if it will be at 128 kbps quality
Explanation:
So, let's say you choose your mp3 be 128 kbps (kilobits per second).
One byte is 8 bits. So 128 kbps = 16 kilobytes per second.
There is 60*60 seconds in one hour. So 16*60*60 = 57.6 megabytes per hour
Multiply by 20 hours to get your answer: 57.6*20 = 1152 MB = 1.152 GB.
