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lesya692 [45]
3 years ago
8

A group of winning ticket holders share equally 90,000,000 lottery. Before the money is divided, three more winning ticket holde

rs are declared. As a result, each persons share is reduced to 5,000,000. How many people were in the original group of winners
Mathematics
1 answer:
Kruka [31]3 years ago
6 0

Let's assume

people were in the original group of winners as x

A group of winning ticket holders share equally 90,000,000 lottery

Before the money is divided, three more winning ticket holders are declared

so, total number of winning tickes =x+3

each persons share is reduced to 5,000,000

so, total money =5,000,000*(x+3)

and this must be equal to total money

5000000(x+3)=90,000,000

now, we can solve for x

and we get

x+3=18

Subtrac both sides by 3

x+3-3=18-3

x=15

so,

number of people were in the original group of winners is 15 ...........Answer

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