Question

A group of winning ticket holders share equally 90,000,000 lottery. Before the money is divided, three more winning ticket holders are declared. As a result, each persons share is reduced to 5,000,000. How many people were in the original group of winners

Answer 1

Let's assume

people were in the original group of winners as x

A group of winning ticket holders share equally 90,000,000 lottery

Before the money is divided, three more winning ticket holders are declared

so, total number of winning tickes =x+3

each persons share is reduced to 5,000,000

so, total money =5,000,000*(x+3)

and this must be equal to total money

$5000000(x+3)=90,000,000$

now, we can solve for x

and we get

$x+3=18$

Subtrac both sides by 3

$x+3-3=18-3$

$x=15$

so,

number of people were in the original group of winners is 15 ...........Answer