We are looking to find P(X>60 students)
X is normally distributed with mean 50 and standard deviation 5
We need to find the z-score of 60 students
To find the probability of P(Z>2), we can do 1 - P(Z<2)
So we read the probability when Z<2 which is 0.9772, then subtract from one we get 0.0228
The number of students that has score more than 60 is 0.0228 x 1000 = 228 students
Answer:
C
Step-by-step explanation:
Multiply the top and bottom, both by sqrtx-sqrt5. This is in order to rationalize the denominators.
You get answer C.
To make this easy let covert everything using a LCD.
The LCD of 1/4 1/12 and 1/6 is 12. This becomes...
Tom ate 3/12 of the pizza.
Leftover pizza = 9/12.
Slices were 1/12.
X friends got pizza.
Remaining pizza is 2/12.
if each friend got 1 piece(1/12)....
9/12(Leftovers) - 2/12(remaining) = 7/12
So 7 friends got pizza.
Answer:
And then replacing in the total probability formula we got:
And rounded we got
That represent the probability that it rains over the weekend (either Saturday or Sunday)
Step-by-step explanation:
We can define the following notaton for the events:
A = It rains over the Saturday
B = It rains over the Sunday
We have the probabilities for these two events given:
And we are interested on the probability that it rains over the weekend (either Saturday or Sunday), so we want to find this probability:
And for this case we can use the total probability rule given by:
And since we are assuming the events independent we can find the probability of intersection like this:
And then replacing in the total probability formula we got:
And rounded we got
That represent the probability that it rains over the weekend (either Saturday or Sunday)
Answer:
Step-by-step explanation:
Circumference formula: