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3 years ago

11

Write a

}{5}x-2" align="absmiddle" class="latex-formula"> in standard form using integers.

1 answer:

erastova [34]3 years ago

3 0

Answer:

4x-5y=10

Step-by-step explanation:

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Solve using the quadratic formula: Y = 2x^2 - 7x-3

algol13

Answer:

x=-0.39 x=3.89

Step-by-step explanation:

a=2

b=-7

c=-3

when you plug all of those numbers in you would get

(7± $\sqrt{73}$ )/ (4)

so x=-0.39 x=3.89 would be your answer

7 0

3 years ago

Find the slope of the line passing through each of the following pairs of points and draw the graph of the line.

tiny-mole [99]

Answer:

The slope is 1/2

Step-by-step explanation:

7 0

3 years ago

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Mrs. Ferree spent $43.50 on BBQ from The Smoke Station. The sales tax rate is 8%. What was her TOTAL cost?

AveGali [126]

Answer:

46.98

Step-by-step explanation:

Multiply the total without taxes by the taxes sales rate:

43.50 x 1.08

=46.98

7 0

3 years ago

Read 2 more answers

for lunch , you must choose a sandwich, a piece of fruit, and a drink. your choices include a ham sandwich, tuna sandwich, or ch

Bogdan [553]

8+8+8+8=32, the concept will catch on. write on a piece of paper all the choices and add them all up

6 0

4 years ago

Find maclaurin series

Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

$\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}$

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

$\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}$

The first 3 terms of the series are

$\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}$

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

$\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}$

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

$\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}$

7 0

3 years ago