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Citrus2011 [14]
3 years ago
11

A bacteria culture doubles twice a day. There are 143,622 bacteria present on day 15. How many were present on day 10?

Mathematics
1 answer:
gtnhenbr [62]3 years ago
8 0

Answer:

140

Step-by-step explanation:

- 143,622 bacteria present on day 15

- the bacteria doubles twice a day

that means each day backwards, the bacteria is four times less the day before

therefore:

- on day 14, the number of bacteria is 143,622 / 4

which is 35,905.5

and so on!

so:

- day 13 = 8,976.375

- day 12 = 2,244.09375

- day 11 =  561.0234375

- day 10 = 140.255859375

this rounded to the nearest whole number is

= 140 bacteria

(you can't have a part of a bacteria!)

hope this helps! :)

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\text{Hey there!}

\mathsf{-\dfrac{5}{2}a+5=25}

\text{\bf{SUBTRACT}}\mathsf{\ by\ 5\ on\ your\ sides}\\\mathsf{-\dfrac{5}{2}a+5-5=25-5}\\\\\mathsf{Cancel\ out: 5-5\ because\ it\ gives\ you\ 0}\\\\\mathsf{Keep: 25 - 5\ because\ it\ helps\ us\ solve\ for\ a}\\\\\mathsf{25-5=20}\\\\\mathsf{New\ equation:- \dfrac{5}{2}a=20}

\text{\bf{MULTIPLY}}\mathsf{\  \dfrac{2}{-5}\ on\ your\ sides}\\\\\mathsf{\dfrac{2}{=5}\times\dfrac{-5}{2}a=\dfrac{2}{-5}\times20}\\\\\mathsf{Cancel\ out: \dfrac{2}{-5}\times\dfrac{-5}{2}\ because\ it\ gives\ you\ 1}\\\\\mathsf{Keep: \dfrac{2}{-5}\times20\ because\ it\ gives\ you\ the\ value\ of\ a}\\\\\mathsf{\dfrac{2}{-5}\times20=-8}

\boxed{\boxed{\boxed{\boxed{\mathsf{Thus\ your\ answer\boxed{\boxed{\mathsf{a=-8}}}}}}}}\checkmark

\large\text{Good luck on your assignment and enjoy your day!}

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atroni [7]

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Step-by-step explanation:

You are looking for what is called  <u>Coterminal Angles</u>.

To find a coterminal angle between 0 and 360 you <u>add or subtract</u> 360.

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